根据管道定界符传递字符串/记录

Question

Please advice as I have list of records but I need to find out if my record has 5 pipe delimiter and first name matches then print it.

For example:

abc|def|ghi|lmno|pq|rs
abc|def|ghi|lmno
abc|def|ghi
dpo|def|ghi|lmno|fr|pl|nm

But I want only 1st value to pass if loop.

if ($string contains "abc" && 5 pipe delimiter )
print $string;

Answer 1

It looks like awk rides to the rescue once more:

awk -F '|' 'NF == 6 && $1 == "abc" { print }'

There are 6 fields if there are 5 delimiters. You could omit the { print } since that's the default action. If you need to pass the value abc to the script (it can vary), use:

awk -F '|' -v string=abc 'NF == 6  && $1 == string { print }'

Don't try using match as a variable name.

My answer is predicated on the question, which says:

if my record has 5 pipe delimiter and first name matches then print it

meaning 'if the record has 6 fields separated by pipe delimiters (so there are 5 pipes) and the first field matches the given name, then print the whole record'. If the question means something slightly different, then the answer has to be modified accordingly.

This is Unix; there are other ways to do the same task, including:

grep '^abc|[^|]*|[^|]*|[^|]*|[^|]*|[^|]*$'
sed -n -e '/^abc\(|[^|]*\)\{5\}$/p'

and you could use Perl or Python or … pick your favourite scripting language. However, the awk solutions are a lot simpler to read than the grep or sed solutions.