[英]RegEx Ignore Case
I've been trying to create a regex which would ignore the casing. 我一直试图创建一个可以忽略外壳的正则表达式。
This is the regex i am trying to use: 这是我试图使用的正则表达式:
/^[A-Za-z0-9._+\-\']+@+test.com$/;
So basically i would want to match any of these 所以基本上我想要匹配任何这些
I tried this, but it doesn't work: 我试过这个,但它不起作用:
/^[A-Za-z0-9._+\-\']+@+(?i)+test.com$/;
I read somewhere about the use of (?i), but couldn't find any examples which show their usage in regex to ignore casing. 我在某处读到了(?i)的使用,但是找不到任何显示它们在regex中用于忽略套管的例子。 Thoughts anyone ?
想什么? Thanks a lot in advance.
非常感谢提前。
Flags go at the end. 旗帜走到尽头。
/regex/i
i
is for case-Insensitive (or ignore-case) i
是针对案例 - 不敏感(或忽略案例)
For anyone else who arrives here looking for this, if you've got code that is using the RegExp
constructor you can also do this by specifying flags as a second argument: 对于到达此处寻找此问题的其他任何人,如果您有使用
RegExp
构造函数的代码,您也可以通过将flags指定为第二个参数来执行此操作:
new RegExp(pattern[, flags])
https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/RegExp https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/RegExp
For example: 例如:
var pattern = /^[A-Za-z0-9._+\-\']+@+test.com$/;
var regExp = new RegExp(pattern, "i");
简单明了,使用以下正则表达式。
(?i)^[A-Za-z0-9._\\-\\']+@test.com$
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