使用Ajax将内容加载到div中

Question

I'm Loading in content from view_login.php into index.php´s div id="display" using ajax javascript

var hr=new XMLHttpRequest();
hr.open("GET", 'view_login.php', true);
hr.onreadystatechange = function(){
    if(hr.readyState == 4 && hr.status == 200){
        var return_data = hr.responseText;
        document.getElementById('display').innerHTML = return_data;
    }
}
hr.send();

Rather than echo $output i would just target the div itself.

PHP/HTML

$output = '
<div id="visible">
<form>
<input type="text" name="name"/>
<input type="submit" />
</form>
</div>';

echo $output;

is it possible to just target the div visible and it contents instead of every ouput on the page? without using jquery and just plain/raw javascript.

Answer 1

There are a few ways of doing this in plain JavaScript. One way would be to append the HTML to a Document Fragment , which is a separate document, then use querySelector on it to pull out just the div you want.

Demo

var frag = document.createDocumentFragment();
var div = document.createElement('div'); // create a div to contain the HTML
div.innerHTML = return_data; // insert HTML to the div
frag.appendChild(div); // append the div to the document fragment

var visibleDiv = frag.querySelector("#visible"); // find the #visible div

// append the div to the main document
document.getElementById('display').appendChild(visibleDiv);

Other options are:

• DOMParser (supported by IE9+).
• Append it as a div to the main document, but you'll need to make sure it's hidden from view, then get the div and remove it.