I'm Loading in content from view_login.php into index.php´s div id="display"
using ajax javascript
var hr=new XMLHttpRequest();
hr.open("GET", 'view_login.php', true);
hr.onreadystatechange = function(){
if(hr.readyState == 4 && hr.status == 200){
var return_data = hr.responseText;
document.getElementById('display').innerHTML = return_data;
}
}
hr.send();
Rather than echo $output
i would just target the div itself.
PHP/HTML
$output = '
<div id="visible">
<form>
<input type="text" name="name"/>
<input type="submit" />
</form>
</div>';
echo $output;
is it possible to just target the div visible
and it contents instead of every ouput on the page? without using jquery and just plain/raw javascript.
There are a few ways of doing this in plain JavaScript. One way would be to append the HTML to a Document Fragment , which is a separate document, then use querySelector
on it to pull out just the div you want.
var frag = document.createDocumentFragment();
var div = document.createElement('div'); // create a div to contain the HTML
div.innerHTML = return_data; // insert HTML to the div
frag.appendChild(div); // append the div to the document fragment
var visibleDiv = frag.querySelector("#visible"); // find the #visible div
// append the div to the main document
document.getElementById('display').appendChild(visibleDiv);
Other options are:
DOMParser
(supported by IE9+).
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