[英]Returning data via WCF service
I want to return latitude
and longitude
variables via WCF to show user's location on the map. 我想通过WCF返回
latitude
和longitude
变量,以在地图上显示用户的位置。 I can return the latitude
, but can't do the same thing with the longitude
, because method returns only one value. 我可以返回
latitude
,但不能对longitude
做同样的事情,因为method仅返回一个值。 I thought about returning array, but don't know how to do that. 我考虑过返回数组,但是不知道该怎么做。 Here is WP code:
这是WP代码:
void proxy_getUsrLatCompleted(object sender, ServiceReference1.getUsrLatCompletedEventArgs e)
{
Grid MyGrid = new Grid();
MyGrid.RowDefinitions.Add(new RowDefinition());
MyGrid.RowDefinitions.Add(new RowDefinition());
MyGrid.Background = new SolidColorBrush(Colors.Transparent);
Rectangle MyRectangle = new Rectangle();
MyRectangle.Fill = new SolidColorBrush(Colors.Black);
MyRectangle.Height = 20;
MyRectangle.Width = 20;
MyRectangle.SetValue(Grid.RowProperty, 0);
MyRectangle.SetValue(Grid.ColumnProperty, 0);
MyGrid.Children.Add(MyRectangle);
Polygon MyPolygon = new Polygon();
MyPolygon.Points.Add(new Point(2, 0));
MyPolygon.Points.Add(new Point(22, 0));
MyPolygon.Points.Add(new Point(2, 40));
MyPolygon.Stroke = new SolidColorBrush(Colors.Black);
MyPolygon.Fill = new SolidColorBrush(Colors.Black);
MyPolygon.SetValue(Grid.RowProperty, 1);
MyPolygon.SetValue(Grid.ColumnProperty, 0);
MyGrid.Children.Add(MyPolygon);
MapOverlay MyOverlay = new MapOverlay();
MyOverlay.Content = MyGrid;
MyOverlay.PositionOrigin = new Point(0, 0.5);
MapLayer MyLayer = new MapLayer();
MyLayer.Add(MyOverlay);
myMap.Layers.Add(MyLayer);
float gLat = float.Parse(e.Result);
myMap.Center = new GeoCoordinate(gLat, gLong);
MyOverlay.GeoCoordinate = new GeoCoordinate(gLat, gLong);
}
You must define a class to hold both properties, and use it as the return value: 您必须定义一个类来包含这两个属性,并将其用作返回值:
class Point
{
public string Lat {get;set;}
public string Lon {get;set}
}
public Point getUsrLocation(string uName)
{
DataClasses1DataContext data = new DataClasses1DataContext();
return (from s in data.Users where s.usrName == uName select new Point(){Lat=s.usrLat,Lon=s.usrLong}).Single();
}
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