Bash和awk做除法

Question

I am trying to do a simple division computation between two integers that will result in a float. I do not want to use bc. This approach works for me for a different purpose with slightly different syntax but I am not quite sure where I am messing up. I am positive that the variables are getting assigned correctly, but I have an error once I try to do the division, and nothing actually gets assigned to the variable. Can anyone help?

Thanks in advance!

rate=`awk '{ shared = "'"${tempRatioArray[0]}"'"; total = "'"${tempRatioArray[1]}"'";\
        printf "%3.0f\t", shared/total }' | awk '{print}'` 

Answer 1

That is not correct way of using shell variables in awk and you don't need 2 awk commands.

Use it like this:

rate=$(awk -v shared="${tempRatioArray[0]}" -v total="${tempRatioArray[1]}" 'BEGIN {
    printf "%.3f", (shared/total) }')

Answer 2

You can use bc :

bc -l <<<"scale=3; 5/2"
2.500

Adapting to your code:

bc -l <<< "scale=3; ${tempRatioArray[0]} / ${tempRatioArray[1]}"