按空格分割字符串会删除换行符

Question

I'm splitting a string by whitespaces, but for some reason the new line characters are being removed. For example:

String[] splitSentence = "Example sentence\n\n This sentence is an example".
   split("\\s+");

splitSentence will contain this:

["Example", "sentence", "This", "sentence", "is", "an", "example"]

and if I make this:

String[] splitSentence = "Example sentence\n\n This sentence is an example".
   split("\\s");

splitSentence will contain this:

["Example", "sentence", "", "", "This", "sentence", "is", "an", "example"]

---

I'm trying to achieve something like this:

["Example", "sentence\n\n", "This", "sentence", "is", "an", "example"]  

Or like this:

["Example", "sentence", "\n", "\n", "This", "sentence", "is", "an", "example"]

I've tried a lot of things with no luck... Any help will be appreciated.

Answer 1

String[] splitSentence = "Example sentence\n\n This sentence is an example".
   split(' ');

this version should work, so empty space will be remove only and not new line.

Answer 2

Split by spaces and tabs (without newline):

String[] splitSentence = "Example sentence\n\n This sentence is an example".split("[ \t]+");

Result: ["Example", "sentence\\n\\n", "This", "sentence", "is", "an", "example"]

Answer 3

In a regex, \\s is defined to be equivalent to the characters in this set:

[ \t\n\x0B\f\r]

(See the javadoc ). If you don't want newlines to be treated like spaces, then you can write your own set:

splitSentence = "Example sentence\n\n This sentence is an example".split("[ \t\\x0B\f\r]+");

(or eliminate other characters you don't want the split to recognize).

( \\t is TAB, \\x0B is vertical tab, \\f is FF (form feed), \\r is CR)

This method seems to produce the second result you mentioned, where the \\n 's are returned as separate strings:

splitSentence = "Example sentence\n\n This sentence is an example".split("[ \t\\x0B\f\r]+|(?=\n)");

This uses lookahead to split at a point that is immediately followed by \\n , but doesn't treat \\n as a delimiter that will be removed from the result.