该虚拟机如何将指令转换为十六进制值？

Question

I'm learning about virtual machines and I came across this Wikipedia book thing, and it's really good. However, I'm at the section where the writer is explaining how he converts instructions such as:

loadi r0 #100

to

0x1064

And I have no idea how it works? Can someone please explain this to me, here's the link in question http://en.wikibooks.org/wiki/Creating_a_Virtual_Machine/Register_VM_in_C

If you scroll down to instruction codes he talks about it, but it doesn't make sense to me, can someone explain to me like I'm 5?

Answer 1

The insctruction of loadi r0 #100 becomes a 16-bit instruction.

The command loadi sets bits 11 to 15 (bits to the left) to 1:

0001xxxxxxxxxxxx

r0 is for register 0, and sets bits 8 to 11.

00010000xxxxxxxx

The value 100 is placed in bits 0 to 7. Bits 4 to 7 are multiplied by 16, then added to value in bits 0 to 3. So 100 = 6 times 16 (equals 96) + 4.

0001_0000_0110_0100 (in binary, seperations for clarity)
1064 (in hexa)

Source: http://en.wikibooks.org/wiki/Creating_a_Virtual_Machine/Register_VM_in_C#Instruction_codes

Answer 2

0x1064 represents a hexidecimal number (base 16).

This number represents multiple pieces of information:
bits 15-12 = 0001 (loadi)
bits 11- 8 = 0000 (register)
bits  7- 0 = 0110 0100 (value to load)

So in binary (base2) the instruction is 0001 0000 0110 0100.
Converting to hex (base 64) the instruction is 0x1064.

You can use a calculator program to help converting between decimal (base 10), binary, and hex.