在Hibernate中查询结果中的行数

Question

I'm facing the following problem:

    Criteria criteria = getSession().createCriteria(User.class);

    ProjectionList projectionList = Projections.projectionList();
    projectionList.add(Projections.property("id"));
    projectionList.add(Projections.countDistinct("friend_id"));
    projectionList.add(Projections.property("registrationDate"));
    projectionList.add(Projections.property("lastLoginDate"));

    criteria.setProjection(projectionList);

this piece of code returns me a couple of entries with the data I require. However, I need the rowcount for it. Is there a clean way of doing this, rather than just doing a:

return criteria.list().size();

?

Answer 1

Criteria criteria = session.createCriteria(Track.class)
                    .setProjection(Projections.rowCount());

            List result = criteria.list();
            if (!result.isEmpty()) {
                Integer rowCount = (Integer) result.get(0);
                System.out.println("Total records: " + rowCount);

Answer 2

What if you add this to the end of the ProjectionList?

Projections.rowCount()

I use the following code to search something and then get the rowcount for it.

Criteria criteria = session.createCriteria(LogEntryOracle.class);
if (search != null && !search.isEmpty()) {
    criteria.add(Restrictions.ilike("xml", search, MatchMode.ANYWHERE));
}

criteria.setProjection(Projections.rowCount());
return (Number) criteria.uniqueResult();

Answer 3

Seems that my problem was caused by the lack of analysis:

Criteria criteria = getSession().createCriteria(User.class);
criteria.setProjection(Projections.countDistinct("id"));

return (Long) criteria.uniqueResult();

since we're already grouping by the user ID then all I had to do is find the amount if unique user IDs matching the search criteria.