用字母和数字解析字符串

Question

Running this method gives a string of total post output

String numberOfPost = test.runNewAdvancedSearch(query, waitTime, startDate, endDate, selectedBrowser, data1, "");

int numberOfPostsInt = Integer.parseInt(numberOfPosts.replace(",", ""));

this parseInt does not work

How do I parse this out below?

"Total Posts: 5,203"

Answer 1

Try this fully functional example:

public class Temp {

    public static void main(String[] args) {

        String s = "Total Posts: 5,203";
        s = s.replaceAll("[^0-9]+", "");
        System.out.println(s);

    }

}

Meaning of the regex pattern [^0-9]+ - Remove all characters which occurs one or more times + which does NOT ^ belong to the list [ ] of characters 0 to 9 .

Answer 2

if comma is decimal separator:

    double d = Double.parseDouble(s.substring(s.lastIndexOf(' ') + 1).replace(",", "."));

if comma is grouping separator:

    long d = Long.parseLong(s.substring(s.lastIndexOf(' ') + 1).replace(",", ""));

Answer 3

Try This:

String numberOfPost = test.runNewAdvancedSearch(query, waitTime, startDate, endDate, selectedBrowser, data1, ""); // get the parse string "Total Posts: 5,203
int index = numberOfPost.lastIndexOf(":");
String number = numberOfPost.substring(index + 1);
int numOfPost = Integer.parseInt(number.replace(",", "").trim());
System.out.println(numOfPost); // 5203enter code here