将字符串转换为数字

Question

Say I have a string phone = "1-800-test"

I need to convert the letters to numbers.

Doing something like this doesn't work (note I'm looping it of course):

phone = phone.replace(phone.charAt(9), (char) getNumber(phone.charAt(9)));

Note that getNumber() is a method that takes a letter and returns a number:

int getNumber(char uppercaseLetter)

Anyway, I get some weird output with the letter replaced by a weird square.

How should I replace the letters with numbers?

Answer 1

(char) 1 is not what you need. You need '1' .

The good way to do that is to create a Map<Character, Character> , pre-populate it: map.put('t', '8') , etc for all letters, and then

for (...) {
   Character letter = phone.charAt(i);
   Character digit = map.get(Character.toLowerCase(letter));
   if (digit != null) {
      phone = phone.replace(letter, digit);
   } 
}

A trivial solution would be to just have one line for each character:

phone = phone.replace('a', '2');
phone = phone.replace('b', '2');
//etc..

(or, for better performance, utilize StringBuilder's replace(..) and indexOf(..) )

Answer 2

Doing (char)1 gives you the ASCII character represented by 1 so you get the weird square. You can just use '1' to instead. If you insist on converting integers to ASCII, just add 48 (since that is where the digits start in the ascii). ie (char)48 is '0', (char)49 is '1' and so on. That doesn't seem necessary for me though.

The exact answer to your question, is use:

phone = phone.replace(phone.charAt(9), (char)(48+getNumber(phone.charAt(9))));

But it is NOT recommended...