[英]Overridden std::ostream flush() function not called by std::flush
I've overridden std::ostream::flush()
function. 我已经覆盖了std::ostream::flush()
函数。 Below I've removed all other code from the example: 下面我从示例中删除了所有其他代码:
#include <iostream>
#include <ostream>
class CMyStream : public std::streambuf, public std::ostream
{
public:
explicit CMyStream() throw() : std::ostream(this)
{
// Intentionally empty block
}
std::ostream &flush()
{
std::cout << "Overridden flush called\n";
return (*this);
}
int sync()
{
std::cout << "Overridden sync called\n";
return 0; // Success
}
};
I try to use it like this: 我试着像这样使用它:
CMyStream myStream;
myStream << "Test" << std::flush;
, but the overridden CMyStream::flush()
or CMyStream::sync()
functions are not called by the std::flush
manipulator. ,但是重写的CMyStream::flush()
或CMyStream::sync()
函数不会被std::flush
操作CMyStream::sync()
调用。 If I debug I see that the default std::ostream::flush()
is called and not my overriden function. 如果我调试我看到默认的std::ostream::flush()
被调用而不是我的覆盖函数。
Is there a way around this problem, or do I have to call myStream.flush()
directly and not with the manipulator? 有没有解决这个问题的方法,或者我是否必须直接调用myStream.flush()
而不是操纵器?
The problem is that std::ostream::flush
method is not virtual, so you cannot properly override it, and you should not. 问题是std::ostream::flush
方法不是虚拟的,所以你不能正确覆盖它,你不应该。 What you should do instead is to create your own buffer class inherited from std::basic_streambuf
or std::basic_filebuf
or std::basic_stringbuf
and override protected int sync()
method in there. 你应该做的是创建自己的缓冲类,继承自std::basic_streambuf
或std::basic_filebuf
或std::basic_stringbuf
并在那里覆盖protected int sync()
方法。 Your stream class then should create proper buffer type in it's constructor. 然后你的流类应该在它的构造函数中创建适当的缓冲区类型。
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