如何使用Numpy / OpenCV屏蔽图像？

Question

I have an image I load with:

im = cv2.imread(filename)

I want to keep data that is in the center of the image. I created a circle as a mask of the area I want to keep.

I created the circle with:

height,width,depth = im.shape
circle = np.zeros((height,width))
cv2.circle(circle,(width/2,height/2),280,1,thickness=-1)

How can I mask out the data outside of the circle from the original image?

masked_data = im * circle

does not work.

Answer 1

Use cv2.bitwise_and and pass the circle as mask.

im = cv2.imread(filename)
height,width,depth = im.shape
circle_img = np.zeros((height,width), np.uint8)
cv2.circle(circle_img,(width/2,height/2),280,1,thickness=-1)

masked_data = cv2.bitwise_and(im, im, mask=circle_img)

cv2.imshow("masked", masked_data)
cv2.waitKey(0)

Answer 2

circle is just a 2D array with 1.0 s and 0.0 s. Numpy needs help to understand what you want to do with the third dimension of your im so you must give it an extra axis and then your line would work.

masked_data = im * circle[..., np.newaxis]

But note that the masking is simply setting the color to (0, 0, 0) for things outside the circle according to your code if the image lacks an alpha-channel.

However you have another potential problem: circle will be of the default data-type (which probably will be float64 or float32 . That's not good for your image, so you should change the line where you create circle to

circle = np.zeros((height, width), dtype=im.dtype)

Answer 3

In this case if you want to have a circular image you must write a new algorithm and first you must be able to access to the coordinates of the pixels. Then you can simply compare pixels that are not within the scope of that circle or not and replace them with some value (or NULL if it's accepted with your image format criteria).

Here is an example:

import cv2
import numpy as np
im = cv2.imread('sss.png')


def facechop(im):

 height,width,depth = im.shape
 #circle = np.zeros((height,width))
 #print circle
 x=width/2
 y=height/2
 circle=cv2.circle(im,(width/2,height/2),180,1,thickness=1)
 #newcameramtx, roi=cv2.getOptimalNewCameraMatrix(im,10,(w,h),1,(w,h))
 cv2.rectangle(im,(x-180,y-180),(x+180,y+180),(0,0,255),2)
 crop_img = im[y-180:y+180,x-180:x+180]
 lastim=np.equal(crop_img,circle)
 #dd=np.logical_and(crop_img,circle)

 for i in range(len(last_im)) :
     if last_im[i].all()==False:
         crop_img[i]=[0,0,0]


 cv2.imshow('im',crop_img)
if __name__ == '__main__':
    facechop(im)
    while(True):
        key = cv2.waitKey(20)
        if key in [27, ord('Q'), ord('q')]:
            break

Answer 4

使用NumPy赋值给索引数组 ：

im[circle == 0] = [0, 0, 0]