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XSLT:将值从一个XML元素注入到另一个XML元素

[英]XSLT:Injecting values from one XML element into another XML element

I am working with a problem and was wondering how than can be done using XSLT(1.0). 我正在处理一个问题,想知道如何使用XSLT(1.0)来完成。 I have combined the data from 2 XML files into a single one. 我已经将2个XML文件中的数据合并为一个文件。 I have to inject values from one XML node into the other. 我必须将值从一个XML节点注入到另一个。 Since my XML files are pretty big, I don't have to luxury of of creating elements in the XSLT. 由于我的XML文件很大,因此不必在XSLT中创建元素。 I would simply like to somehow map them from one data1 elements to data2 elements. 我只是想以某种方式将它们从一个data1元素映射到data2元素。

Input: 输入:

<combinedData>
<data1>
    <element1>
        <id>12</id>
        <name>Tony Green</name>
        <address>Home Address</address>
    </element1>
</data1>
<data2>
    <element1>
        <element2>
            <element3>
                <IdOfPerson></IdOfPerson>
                <NameOfPerson></NameOfPerson>
                <addressOfPerson></addressOfPerson>
            </element3>
        </element2>
    </element1>        
</data2>  

Desired Output: 所需输出:

<data2>
<element1>
    <element2>
        <element3>
            <IdOfPerson>12</IdOfPerson>
            <NameOfPerson>Tony Green</NameOfPerson>
            <addressOfPerson>Home Address</addressOfPerson>
        </element3>
    </element2>
</element1>        

Any help with this will be highly appreciated. 任何帮助,将不胜感激。

Use the identity transform to copy data2 : 使用身份转换来复制data2

<xsl:template match="/">
  <xsl:apply-templates select="//data2"/>
</xsl:template>

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"></xsl:apply-templates>
  </xsl:copy>
</xsl:template>

Use a specific template for the child nodes of element3 . element3的子节点使用特定的模板。 I am assuming that you want to copy the data from the lower-case nodes of the same name of data1/element1 : 我假设您要从具有相同名称data1/element1的小写节点复制数据:

<xsl:template match="element3/node()">
  <xsl:variable name="name-without-of-person" select="substring-before(name(), 'OfPerson')" />
  <xsl:variable name="lower-case" select="translate($name-without-of-person, 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz')"/>
  <!-- copy the original node -->
  <xsl:copy>
    <!-- XSLT 1.0 does not support XPath queries that are dynamically generated,
         therefore, .../element1/$lower-case does not work.
         However, using a predicate with a name() query works -->
    <xsl:value-of select="/combinedData/data1/element1/*[name()=$lower-case]"/>
  </xsl:copy>
</xsl:template>

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