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如何从Android中的JSON解析中深拉对象/数组

[英]How do I pull objects/array deep from a JSON parse in Android

JSON code: http://headytunes.co/?json=1 JSON代码: http//headytunes.co/?json = 1

I am trying to pull the author name, but only repeating the first author in the JSON list. 我试图提取作者姓名,但只重复JSON列表中的第一位作者。 I am also trying to pull the thumbnail image and the multiple categories that come up from this JSON, but I can't correctly pull the image or the tags. 我也试图拉出缩略图和来自这个JSON的多个类别,但我无法正确拉动图像或标签。

     HttpEntity entity = response.getEntity();
                String data = EntityUtils.toString(entity);
                Actors actor = new Actors();
                JSONObject jsono = new JSONObject(data);
                JSONArray jarray = jsono.getJSONArray("posts");
                JSONObject jsonoTwo =jsono.getJSONArray("posts").getJSONObject(0).getJSONObject("author");

                for (int i = 0; i < jarray.length(); i++) {
                    JSONObject object = jarray.getJSONObject(i);

                    actor = new Actors();

                    actor.setName(object.getString("title"));
                    actor.setDescription(object.getString("excerpt"));
                    actor.setDate(object.getString("date"));
                    actor.setAuthor(jsonoTwo.getString("name"));
                    //.setTags(jsonoThree.getString("title"));
                    //actor.setImage(images.getString("url"));

                    songList.add(actor);

You are only getting the first author name repeatedly because that is what you are doing in your code. 您只是重复获取第一个作者姓名,因为这是您在代码中所做的。

You currently have: 你目前有:

JSONObject jsonoTwo = jsono.getJSONArray("posts"). JSONObject jsonoTwo = jsono.getJSONArray(“posts”)。 getJSONObject(0) .getJSONObject("author"); getJSONObject(0) .getJSONObject(“author”);

. .

actor.setAuthor(jsonoTwo.getString("name")); actor.setAuthor(jsonoTwo.getString( “名称”));

The bolded part above is saying to grab the data of the first post then grab the author. 上面的粗体部分是说抓住第一篇文章的数据然后抓住作者。

Update your code so that it looks like: 更新您的代码,使其看起来像:

actor.setAuthor(object.getJSONObject("author").getString("name"));

I hope it dose not have any typo : 我希望它没有任何拼写错误:

for (int i = 0; i < jarray.length(); i++) {
                        JSONObject object = jarray.getJSONObject(i);

                        actor = new Actors();

                        actor.setName(object.getString("title"));
                        actor.setDescription(object.getString("excerpt"));
                        actor.setDate(object.getString("date"));
                        actor.setAuthor(object.getString("name"));

                        JSONArray tags = object.getJSONArray("tag");
                        for (int j = 0; j < tags.length(); j++) {
                          // you can access each tag in this section 
                        }

                        JSONArray attachment = object.getJSONArray("attachment");
                        for (int k = 0; k < tags.length(); k++) {
                          // you can access inside attachment 
                        JSONObject insideAttachmentObj = attachment.getJSONObject(k);
                        insideAttachmentObj.getJSONObject("images").getJSONObject("thumbnail");
                        //or for accessing url :insideAttachmentObj.getJSONObject("images").getJSONObject("thumbnail").getString("url");
                        }



                        songList.add(actor);

You can simplify this whole process by looking at using Gson to create model classes from raw JSON. 您可以通过使用Gson从原始JSON创建模型类来简化整个过程。

To create a model class, simply have attributes of the same name as they are in the returned JSON, then parse your JSON into a list of models like such: 要创建模型类,只需使用与返回的JSON中相同名称的属性,然后将JSON解析为如下模型列表:

//Example model class
public Class Actor{
  String name;
}

....

//Where you are parsing JSON

public void parseJSON(String json){
  List<Actor> actors= Arrays.toList(new Gson().fromJson(json, Actor[].class));
  //Use the actor object
}

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