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如何使用Android上的Jackson将JSON数组解析为不同的对象?

[英]How do I parse a JSON array into different objects using Jackson on Android?

I'm trying to parse JSON like the following into object using Jackson on Android (Note: I'm not in control of the JSON format - the format comes from Yammer) 我正在尝试在Android上使用Jackson将类似以下的JSON解析为对象(注意:我不受JSON格式的控制-该格式来自Yammer)

"references": [
    {
        "type": "user",
        "id": 12345678,
        "name": "Wex"
    },
    {
        "type": "message",
        "id": 12345679,
        "body":
        {
            "plain":"A short message"
        }
    },
    {
        "type": "thread",
        "id": 12345670,
        "thread_starter_id": 428181699
    }
]

The problem is that each entry in references is a different type of object with different properties. 问题在于references中的每个条目都是具有不同属性的不同类型的对象。 As a start I've got: 首先,我得到了:

public static class Reference
{
    public String type;
    public String id;
}

I'd rather avoid putting all potential properties in one object like: 我宁愿避免将所有潜在属性放在一个对象中,例如:

public static class Reference
{
    public static class Body
    {
        public String plain;
    }
    public String type;
    public String id;
    public String name;
    public Body body;
    public String thread_starter_id;
}

And want to use separate classes that are created dependant on the type value like: 并希望使用根据type值创建的单独的类,例如:

public static class ReferenceUser extends Reference
{
    public String name;
}

public static class ReferenceMessage extends Reference
{
    public static class Body
    {
        public String plain;
    }
    public Body body;
}

public static class ReferenceThread extends Reference
{
    public String thread_starter_id;
}

So... what's the best way of getting Jackson to parse the JSON like that? 那么...让Jackson像这样解析JSON的最佳方法是什么?

I'm currently parsing it quite simply like this: 我目前正在像这样简单地解析它:

ObjectMapper mapper = new ObjectMapper();
Reference[] references = mapper.readValue(json, Reference[].class);

you can do something like this with Jackson: 您可以使用Jackson进行以下操作:

@JsonTypeInfo(
    use = JsonTypeInfo.Id.NAME,
    include = JsonTypeInfo.As.PROPERTY,
    property = "type")
@JsonSubTypes({
    @JsonSubTypes.Type(name = "user", value = ReferenceUser.class),
    @JsonSubTypes.Type(name = "message", value = ReferenceMessage.class),
    @JsonSubTypes.Type(name = "thread", value = ReferenceThread.class)
})

public class Reference {
    int id;
    String name;
}

This way you will generate subclasses. 这样,您将生成子类。

John 约翰

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