JavaScript json_encode中的PHP数组不起作用

Question

I have a php page that connects to mysql database, performs a query, stores its result as an array as a session variable.

$_SESSION['array1']=$array1;

This variable is received by another php page within same directory like this:

session_start();
$array1= $_SESSION['array1'];

Now, in the same php page itself, I have a javascript code that intends to access this $array1 and print its value. I found similar questions online and got to know about json_encode function but couldn't get it done. Code:

<script type="text/javascript">
var jsarray= <?php json_encode($array1); ?>;
document.write (jsarray[2]);   </script>

I am just trying to print the 2nd index of array through javascript but haven't been able to do so. Nothing is displayed at all. I can see that I can print array on the second page using php but I need javascript code to be able to access the array. If I provide values to jsaraay in javascript code like:

var jsarray=[1,2,3,4,5];

and i print 2nd index,

document.write(jsarray[2]);

The output is correct. I want to access php array the same way. Please help?

Answer 1

You need to echo the json:

var jsarray= <?php echo json_encode($array1); ?>;

Online sample here .

Answer 2

If i write

$array = [1, 2, 3];
print('<script> jsarray = ' . json_encode($array) . ';</script>');

then I can access jsarray in my javascript.

Note that jsarray[2] wil return the 3rd index, not the 2nd (indices start at 0). You can also check your javascript console (F12 on Chrome + Firefox, then select console tab) for errors.

Answer 3

try this way:

<script>
var jsArray = ["<?php echo join("\", \"", $array1); ?>"];
alert(jsArray);
</script>

That should work