使用json_encode将PHP数组传递给javascript会出错？

Question

I fetch some information from DB - shown here:

$link = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
    $link->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $handle = $link->prepare("SELECT dropAddress FROM mv_bookingEst WHERE userID='$userID'"); 
    $handle->execute();
    $result = $handle->fetchAll(\PDO::FETCH_OBJ);
    //print_r($result);
    $x = 0;
    foreach($result as $obj){
         $resultArray[$x] = $obj->dropAddress;
         $x++;
    }

and then in my javscript:

var count = "<?php echo json_encode($resultArray); ?>";

However I get the following error:

Syntax error: unexpected number --> var count = "["-33.8935642, 151.20227810000006","-33.857653, 151.20853699999998 ...

If I replace json_encode($resultArray) with echo ($resultArray[0]) the values pass fine. Not sure how to fix it because everything I've read uses this method. TIA

Answer 1

 var count = "<?php echo json_encode($resultArray); ?>"; 

You are returning the result of the json_encode inside of a JavaScript string. Your syntax error shows this:

 Syntax error: unexpected number --> var count = "["-33.8935642, 151.20227810000006","-33.857653, 151.20853699999998 ... 

Unless there's a failure in coversion, json_encode returns valid JavaScript syntax , so you should just use it as-is without any adornments in your javascript:

var count = <?php echo json_encode($resultArray); ?>;

If you want to take into consideration the possibility of failure, then you can use this instead:

var count = <?php
     $tmp = json_encode($resultArray);
     echo ($tmp === false ? 'null' : $tmp);
?>;