[英]How to add multiple columns to a data.frame in one go?
I have following dataframe and vector:我有以下数据框和向量:
ddf = data.frame(a=rep(1,10), b=rep(2,10))
xx = c("c", "d", "e", "f")
How can I new empty columns which are named with items in xx ?如何新建以 xx 中的项目命名的空列?
I tried following but it does not work:我尝试了以下但它不起作用:
ddf = cbind(ddf, data.frame(xx))
Error in data.frame(..., check.names = FALSE) :
arguments imply differing number of rows: 10, 4
Following also does not work:以下也不起作用:
for(i in 1:length(xx)){
ddf$(xx[i]) = ""
}
Error: unexpected '(' in:
"for(i in 1:length(xx)){
ddf$("
}
Error: unexpected '}' in "}"
This will get you there:这会让你到达那里:
ddf[xx] <- NA
# a b c d e f
#1 1 2 NA NA NA NA
#2 1 2 NA NA NA NA
#3 1 2 NA NA NA NA
#...
You can't directly use something like ddf$xx
because this will try to assign to a column called xx
rather than interpreting xx
.您不能直接使用ddf$xx
类的东西,因为这会尝试分配给名为xx
的列,而不是解释xx
。 You need to use [
and [<-
functions, using the square brackets when you are dealing with a character string/vector - like ddf["columnname"]
or ddf[c("col1","col2")]
, or a stored vector like your ddf[xx]
.您需要使用[
和[<-
函数,在处理字符串/向量时使用方括号 - 如ddf["columnname"]
或ddf[c("col1","col2")]
,或存储向量,如您的ddf[xx]
。
The reason why it selects columns is because data.frames
are lists essentially:它选择列的原因是因为data.frames
本质上是列表:
is.list(ddf)
#[1] TRUE
as.list(ddf)
#$a
# [1] 1 1 1 1 1 1 1 1 1 1
#
#$b
# [1] 2 2 2 2 2 2 2 2 2 2
...with each column corresponding to a list entry. ...每列对应一个列表条目。 So if you don't use a comma to specify a row, like ddf["name",]
or a column like ddf[,"name"]
, you get the column by default.因此,如果您不使用逗号来指定行,如ddf["name",]
或列如ddf[,"name"]
,则默认情况下您将获得该列。
In the case that you are working with a 0-row dataset, you can not use a value like NA
as the replacement.如果您使用的是 0 行数据集,则不能使用NA
之类的值作为替换。 Instead, replace with list(character(0))
where character(0)
can be substituted for numeric(0)
, integer(0)
, logical(0)
etc, depending on the class you want for your new columns.相反,替换为list(character(0))
,其中character(0)
可以替换为numeric(0)
、 integer(0)
、 logical(0)
等,具体取决于您想要用于新列的类。
ddf <- data.frame(a=character())
xx <- c("c", "d", "e", "f")
ddf[xx] <- list(character(0))
ddf
#[1] a c d e f
#<0 rows> (or 0-length row.names)
This seems to succeed:这似乎成功了:
> cbind(ddf, setNames( lapply(xx, function(x) x=NA), xx) )
a b c d e f
1 1 2 NA NA NA NA
2 1 2 NA NA NA NA
3 1 2 NA NA NA NA
4 1 2 NA NA NA NA
5 1 2 NA NA NA NA
6 1 2 NA NA NA NA
7 1 2 NA NA NA NA
8 1 2 NA NA NA NA
9 1 2 NA NA NA NA
10 1 2 NA NA NA NA
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.