Python中的if和elif以获得良好的编程习惯

Question

Hello there I'm currently trying to get a good grasp of the if, elif, else structure in Python. I'm trying some weird combinations in python having a test program to know the output in this if, if, elif, elif, else code. However I'm getting weird results such as this

input = raw_input('Please enter the required digit: ')
intput = int(input)

if intput == 0:
    print 'if1'

if intput == 1:
    print 'if2'
elif intput == 0:
    print 'elif1'
elif intput == 1:
    print 'elif2'
else:
    print 'else'

if I in put 1 it will print "if2", I thought that it will also print "elif2" and other shenanigans when I try to change the "intput == n" code. So my question is do I have to stick to the if,elif, elif, .... n * elifs, else method which seems to me working alright than working with the wacky if,if.... n * ifs, elif, elif, ...n* elifs, else.

Thanks

Answer 1

The elif tree is designed such that at anywhere along if one of the statement turns out to be True , the rest of the elif s will not be evaluated.

Here's a tutorial that might help you understand if else better.

Answer 2

this may be more clear to understand:

if input == 0:
    print "if1"

switch(input):
    case 1:
        print "if2"
        break
    case 0:
        print "elif1"
        break
    case 1:
        print "elif2"
        break
    default:
        print "else"
        break

of course, the code does not work.