从一个表中获取唯一的行，而列引用在另一个表中没有

Question

I've two table first Name orders
2nd named printing
orders table structure like this

id job_code job_name qty
1 597 xyz 1000
2 598 lmn 2500
3 599 oqr 20000
4 600 odc 15000

and printing table structure like this

id job_code dispatch qty
1 598 yes 1800
2 600 yes 1456

i want to select all job.code From orders which is not in printing table

I tried myself with this query.

SELECT DISTINCT orders.job_code, orders.job_name, orders.qty FROM orders  
INNER JOIN printing
ON orders.job_code <> printing.job_code ORDER BY orders.job_code DESC LIMIT 10;

OR

SELECT DISTINCT orders.job_code, orders.job_name, orders.qty FROM orders  
INNER JOIN printing
ON orders.job_code NOT IN (printing.job_code) ORDER BY orders.job_code DESC
LIMIT 10;

but it'll return all jobs which held on orders and printing tables

Answer 1

select job_code from orders 
where job_cobe not in (select job_code from printing)

Answer 2

You can use this query.

SELECT
    DISTINCT orders.job_code, orders.job_name, orders.qty 
FROM
    orders 
WHERE
    orders.job_code
    NOT IN
        (SELECT printing.job_code FROM printing)
ORDER BY
    orders.job_code DESC
LIMIT 10

Answer 3

use the query like this

SELECT job_code FROM `orders` left join printingorders on orders.job_code not in ( select job_code from printingorders)

This will give you the result. I tried in my Phpmyadmin.