從一個表中獲取唯一的行，而列引用在另一個表中沒有

Question

我有兩個表，第一個名字orders
第二次命名printing
orders表結構是這樣的

id job_code job_name qty
1 597 xyz 1000
2 598 lmn 2500
3 599 oqr 20000
4 600 odc 15000

和這樣printing表結構

id job_code dispatch qty
1 598 yes 1800
2 600 yes 1456

我想從不在printing表中的orders選擇所有job.code

我嘗試使用此查詢。

SELECT DISTINCT orders.job_code, orders.job_name, orders.qty FROM orders  
INNER JOIN printing
ON orders.job_code <> printing.job_code ORDER BY orders.job_code DESC LIMIT 10;

要么

SELECT DISTINCT orders.job_code, orders.job_name, orders.qty FROM orders  
INNER JOIN printing
ON orders.job_code NOT IN (printing.job_code) ORDER BY orders.job_code DESC
LIMIT 10;

但是它將返回orders和printing表上保留的所有作業

Answer 1

select job_code from orders 
where job_cobe not in (select job_code from printing)

Answer 2

您可以使用此查詢。

SELECT
    DISTINCT orders.job_code, orders.job_name, orders.qty 
FROM
    orders 
WHERE
    orders.job_code
    NOT IN
        (SELECT printing.job_code FROM printing)
ORDER BY
    orders.job_code DESC
LIMIT 10

Answer 3

使用這樣的查詢

SELECT job_code FROM `orders` left join printingorders on orders.job_code not in ( select job_code from printingorders)

這將為您提供結果。 我在Phpmyadmin中嘗試過。