如何将模板类存储在向量中？

Question

I've following code and i want to store Base<A> * a,Base<B> * b in a vector without losing typename,so i want to achieve vector<.....> vec; vec.push_back(a); vec.push_back(b); vector<.....> vec; vec.push_back(a); vec.push_back(b); and call like this vec[0]->DoJob(3,4); vector[1]->DoJob(3,4,"blablba"); vec[0]->DoJob(3,4); vector[1]->DoJob(3,4,"blablba"); . How can i do it? I can change design completely if there is a way to accomplish this.

/*this code works*/
template<typename T>
class Base{
protected:
    virtual ~Base(){}
public:
    template<typename ... Args>
    void DoJob(Args ... args){
        T * t = dynamic_cast<T*>(this);
        t->print(args...);
    }
};


class A:public Base<A>{
public:
    void print(int a, int b){
        cout << a << b << endl;
    }
};

class B :public Base<B>{
public:
    void print(float a, double b, string s){
        cout << a << b << s << endl;
    }
};


Base<A> * a = new A();
a->DoJob(3, 4);
Base<B> * b = new B();
b->DoJob(3, 4,"blabla");

Answer 1

One fairly common way to implement something like that would be to have a container with a pointer to a common superclass.

class BaseSuperclass {
// ...
};

template<typename T> class Base : public BaseSuperclass {
// ...
};

std::vector<BaseSuperclass *> vector;

Then any Base<T> * can be pushed into your vector.

Note that when you iterate over, or retrieve the contents of your vector, all you'll end up getting back is a BaseSuperclass * . You'll then have to figure out which subclass you have at hand.