使用Contains方法检查字符串中的多个单词

Question

I want to check multiple words in a string and want to replace them. Suppose that my string is

str= 20148(R)/(work)24553(r)
if(str.contains(("R)" || str.Contains("(work)"))
{
   //Here I have to replace (R) and (Work) with space "". 
   // so that my string should be like this 20148/24553
}

How can check multiple words not by using loops, and in one flow. I am new to c#. Please help me out

Answer 1

You don't need the if, just do:

var newStr = str.Replace("(R)"," ").Replace("(work)"," ");

If you want a space as you say or:

var newStr = str.Replace("(R)",string.Empty).Replace("(work)",string.Empty);

If you want an empty string.

Answer 2

You could use the Regex.Replace method.

string str = "20148(R)/(work)24553(r)";
string str2 = Regex.Replace(str, "[(](?:R|work)[)]", "", RegexOptions.IgnoreCase);
Console.Writeline(str2); //prints 20148/24553

This says take the string str and match the pattern [(R|work)] and replace any instances with "" ignoring the case of the input string when doing the comparison (so it matches (R) and (r) ).

Answer 3

Put R and r inside a character class to match both letters.

string str = "20148(R)/(work)24553(r)";
string result = Regex.Replace(str, @"\((?:[Rr]|work)\)", "");
Console.WriteLine(result);

IDEONE

OR

string str = "20148(R)/(work)24553(r)";
string result = Regex.Replace(str, @"(?i)\((?:R|work)\)", "");
Console.WriteLine(result);

IDEONE

Pattern Explanation:

• (?i) ( i modifier ) would turn on the case-insensitive mode. So it would match both upper and lowercase letters.
• \\( Matches a literal ( symbol.
• (?:) Non-capturing group.
• R|work Matches a letter R or string work .(case-insensitive match)
• \\) Matches a literal ) symbol.

Answer 4

With regex you can replace this

[(]\b(?:R|work)\b[)]

With empty string ""

Edit:

 string str1 = "20148(R)/(work)24553(r)"; 
  string str2 = Regex.Replace(str1, "[(]\b(?:R|work)\b[)]", "", RegexOptions.IgnoreCase);
  Console.Writeline(str2);