[英]python regex search pattern
I'm searching a block of text for a newline followed by a period. 我正在搜索一段换行符后跟一个句点的文本。
pat = '\n\.'
block = 'Some stuff here. And perhaps another sentence here.\n.Some more text.'
For some reason when I use regex to search for my pattern it changes the value of pat (using Python 2.7). 由于某种原因,当我使用正则表达式搜索模式时,它会更改pat的值(使用Python 2.7)。
import re
mysrch = re.search(pat, block)
Now the value of pat has been changed to: 现在pat的值已更改为:
'\n\\.'
Which is messing with the next search that I use pat for. 这与我使用pat进行的下一次搜索搞混了。 Why is this happening, and how can I avoid it? 为什么会发生这种情况,我该如何避免呢?
Thanks very much in advance in advance. 提前非常感谢。
The extra slash isn't actually part of the string - the string itself hasn't changed at all. 多余的斜杠实际上不是字符串的一部分-字符串本身完全没有改变。
Here's an example: 这是一个例子:
>>> pat = '\n\.'
>>> pat
'\n\\.'
>>> print pat
\.
As you can see, when you print pat, it's only got one \\
in it. 如您所见,当您打印pat时,其中只有一个\\
。 When you dump the value of a string it uses the __repr__
function which is designed to show you unambiguously what is in the string, so it shows you the escaped version of characters. 当您转储字符串的值时,它将使用__repr__
函数,该函数旨在清楚地向您显示字符串中的内容,因此它向您显示字符的转义版本。 Like \\n
is the escaped version of a newline, \\\\
is the escaped version of \\
. 就像\\n
是换行符的转义版本一样, \\\\
是\\
的转义版本。
Your regex is probably not matching how you expect because it has an actual newline character in it, not the literal string "\\n"
(as a repr: "\\\\n"
). 您的正则表达式可能与您的期望不符,因为其中有一个实际的换行符,而不是文字字符串"\\n"
(作为代表: "\\\\n"
)。
You should either make your regex a raw string (as suggested in the comments). 您应该使正则表达式成为原始字符串(如注释中所建议)。
>>> pat = r"\n\."
>>> pat
'\\n\\.'
>>> print pat
\n\.
Or you could just escape the slashes and use 或者您可以逃脱斜线并使用
pat = "\\n\\."
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