正则表达式模式搜索日期格式 MMDDYYYY（python）

Question

I have a list of dates, I want to search for MMDDYYYY or DDMMYYYY or YYYYMMDD using regex. I have been using dateutil and regex pattern to find them but I later realized that dateutil doesn't match for this formats. SO I used regex but the regex pattern matches all kind of values(eg: 55122020 )maybe it is counting it has integers. Is there any pattern which can able to match this kind of Date formats?

lst = ['2020/12/22','20200322', '34252020']
D = r'^(?:(?:19|20)\d{2}([-/]?)\d{1,2}\1\d{1,2}|\d{1,2}([-/]?)\d{1,2}\2(?:19|20)\d{2})$'
for i in lst:
    if re.search(D, str(i)) != None:
        print(i)
    else:
        print('not matched')

Output:
2020/12/22
20200322
34252020

But in actual real world the last value is invalid so the output should be 'not matched'. Is there any pattern which matches this scenario?

Actual output:
2020/12/22
20200322
not matched

Answer 1

You can use the built-in dateutil.parser.parse()

from dateutil.parser import parse

dates = ['2020/12/22','20200322', '34252020']
for d in dates:
    try:
        d = parse(d)
        print(d)
    except:
        print(d, "isn't a date")

---

2020-12-22 00:00:00
2020-03-22 00:00:00
34252020 isn't a date

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Demo

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Note:

To parse multiple dates in a str , you may also want to use datefinder :