正则表达式以首字母开头并且包含一个单词

Question

var str = "I dont have any one";
var str1 = "We dont have any one";
var str2 = "I dont have any more";
var str2 = "I dont have any two";

for these string need to find a reg like it should match string starts with "I" AND contains "one" or "two".

var regx = "/^I/";        //this starts with I
var regx = "/(one|two)/";  //this match one or two

But how to combain both with an AND ?

So str1.test(regx) should be false.

Answer 1

Just match any character between I and one

var str = "I dont have any one";
var str1 = "We dont have any one";
var str2 = "I dont have any more";
var str3 = "I dont have any two";

var regx = /^I.*(one|two)/

console.log(regx.test(str)) // True
console.log(regx.test(str1)) // False
console.log(regx.test(str2)) // False
console.log(regx.test(str3)) // True

Here a fiddle to test

Answer 2

different approach ...

var regx1 = /^I/;        //this starts with I
var regx2 = /(one|two)/;  //this match one or two

// starts with "I" AND contains "one" or "two".
var match = regx1.test(str1) && regx2.test(str1)

Answer 3

It would be better if you add a word boundary.

var regx = /^I.*? (?:one|two)( |\b).*$/;

DEMO