正则表达式以首字母开头并且包含一个单词

Question

var str = "I dont have any one";
var str1 = "We dont have any one";
var str2 = "I dont have any more";
var str2 = "I dont have any two";

对于这些字符串，需要找到一个类似的reg，它应该匹配以“ I”开头且包含“一个”或“两个”的字符串。

var regx = "/^I/";        //this starts with I
var regx = "/(one|two)/";  //this match one or two

但是如何将AND与AND结合使用？

因此str1.test(regx)应该为false。

Answer 1

只要匹配I和one之间的任何字符

var str = "I dont have any one";
var str1 = "We dont have any one";
var str2 = "I dont have any more";
var str3 = "I dont have any two";

var regx = /^I.*(one|two)/

console.log(regx.test(str)) // True
console.log(regx.test(str1)) // False
console.log(regx.test(str2)) // False
console.log(regx.test(str3)) // True

在这里测试

Answer 2

不同的方法...

var regx1 = /^I/;        //this starts with I
var regx2 = /(one|two)/;  //this match one or two

// starts with "I" AND contains "one" or "two".
var match = regx1.test(str1) && regx2.test(str1)

Answer 3

如果添加单词边界会更好。

var regx = /^I.*? (?:one|two)( |\b).*$/;

演示