r：如何使用lapply删除多个数据帧中来自单独列表的行号

Question

I have many data frames organized in a list object. And I have a second list of vectors, that contain row numbers that I want to remove in my data frames. The rows to be removed are different for each data frame. Therefore the number of elements in the list of data frames is equal to the number of elements in the list of vectors. Here the code I've tried out:

test_list<-vector(mode="list",5)
test_list<-lapply(test_list, function(x) data.frame(1,1:10,"c"))
vec_list<-vector(mode="list",5)
vec_list<-lapply(vec_list, function (x) x<-sample(seq(1,10),4))
clean_list<-lapply(test_list, function (x,y) clean_list<-x[-y,],vec_list)

Answer 1

当具有多个对应对象列表时，使用Map或mapply函数比lapply更自然地使用。

Map(function(l, v) l[-v,], test_list, vec_list)

Answer 2

If you want to use lapply , one way is:

  lapply(seq_along(test_list), function(i) test_list[[i]][-vec_list[[i]],])

Benchmarks

On a medium list data,

 set.seed(45)
 test_list<-vector(mode="list",25e3)
 test_list<-lapply(test_list, function(x) data.frame(1,1:10,"c"))
 vec_list<-vector(mode="list",25e3)
 vec_list<-lapply(vec_list, function (x) x<-sample(seq(1,10),4))

 library(microbenchmark)
 f1 <- function() lapply(seq_along(test_list), function(i) test_list[[i]][-vec_list[[i]],])
 f2 <- function() Map(function(l, v) l[-v,], test_list, vec_list)

 microbenchmark(f1(), f2(), unit="relative", times=25L)
 #Unit: relative
 #expr       min        lq  median       uq       max neval
 #f1() 0.9874164 0.9977816 1.00573 1.000419 0.9837334    25
 #f2() 1.0000000 1.0000000 1.00000 1.000000 1.0000000    25