如何将变量作为临时文件传递给bash中的命令

Question

There exists a command foo which expects two arguments which are filenames and which prints some stuff on stdout.

I have a Bash script with two variables a and b holding two strings.

I wish to pass to foo two filenames where the contents of those files are a and b . I then want to store the stdout as a new variable c .

Following ad hoc Googling, the script would perhaps look something like:

a=...;
b=...;
c=`foo <($a) <($b)`;

What should it look like?

Answer 1

a=...
b=...
c=$(foo <(echo "$a") <(echo "$b"))

echo "$c"

Answer 2

Try using echo -e

a=...
b=...
c=$(foo <(echo -e "$a") <(echo -e "$b"))

echo -e "$c"