Bash：如何将变量传递给命令
[英]Bash: How to pass a variable to a command
问题描述
I need to substract 10 minutes from a given time.
我需要从给定时间减去 10 分钟。
As I understand from previous answers, there are solutions only for given constant input, for example:正如我从以前的答案中了解到的那样，只有给定的恒定输入才有解决方案，例如：
date --date '20140202 11:45:30 UTC -10 min'
But in my script, a given date is read from file and I have it as argument, for example:但是在我的脚本中，从文件中读取给定的日期并将其作为参数，例如：
myDate="20140202 11:45:30"
How can I pass this argument (myDate) to the command above?如何将此参数(myDate)传递给上面的命令？
1 个解决方案
解决方案1
0 2016-01-18 09:06:46
myDate="20140202 11:45:30"
date --date "${myDate} UTC -10 min"
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.
相关问题
如何在 bash 命令中传递变量？ - How to pass variable in bash command?
如何在bash中为php命令传递变量 - How to pass variable in bash for php command
如何将命令的一部分作为变量bash传递？ - How to pass parts of a command as variable bash?
如何将变量作为临时文件传递给bash中的命令 - How to pass a variable as a temporary file to a command in bash
如何将awk变量传递给bash命令 - How to pass an awk variable to a bash command
如何在 bash 脚本中将变量传递给 curl 命令？ - How to pass a variable to a curl command in a bash script?
将bash变量传递给perl命令 - Pass a bash variable to a perl command
使用Python将变量传递给bash命令 - Pass variable to bash command with Python
如何在 bash 的 aws cli 命令中传递变量？ - How can I pass a variable in aws cli command in bash?
如何通过bash中的变量传递带有空格的命令行参数 - How to pass command line arguments with spaces through a variable in bash
相关标签