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如何将subprocess.call()输出推送到终端和文件?

[英]How do I push a subprocess.call() output to terminal and file?

I have subprocess.call(["ddrescue", in_file_path, out_file_path], stdout=drclog) . 我有subprocess.call(["ddrescue", in_file_path, out_file_path], stdout=drclog) I'd like this to display the ddrescue in the terminal as it's running and write the output to the file drclog. 我希望在运行时在终端中显示ddrescue并将输出写入文件drclog。 I've tried using subprocess.call(["ddrescue", in_file_path, out_file_path], stdout=drclog, shell=True) , but that gives me an input error into ddrescue. 我试过使用subprocess.call(["ddrescue", in_file_path, out_file_path], stdout=drclog, shell=True) ,但这给了我ddrescue输入错误。

If ddrescue doesn't change its output if its stdout/stderr are redirected to a pipe then you could use tee utility, to display output on the terminal and to save it to a file: 如果ddrescue的stdout / stderr重定向到管道时ddrescue不会更改其输出,则可以使用tee实用程序在终端上显示输出并将其保存到文件中:

$ ddrescue input_path output_path ddrescue_logfile |& tee logfile

If it does then you could try to provide a pseudo-tty using script utility: 如果确实如此,那么您可以尝试使用script实用程序提供一个伪tty:

$ script -c 'ddrescue input_path output_path ddrescue_logfile' -q logfile

If it writes directly to a terminal then you could use screen to capture the output: 如果它直接写到终端,则可以使用screen捕获输出:

$ screen -L -- ddrescue input_path output_path ddrescue_logfile

The output is saved in screenlog.0 file by default. 默认情况下,输出保存在screenlog.0文件中。


To emulate the tee -based command in Python without calling tee utility: 要在Python中模拟基于tee的命令而不调用tee实用程序,请执行以下操作:

#!/usr/bin/env python3
import shlex
import sys
from subprocess import Popen, PIPE, STDOUT

command = 'ddrescue input_path output_path ddrescue_logfile'
with Popen(shlex.split(command), stdout=PIPE, stderr=STDOUT, bufsize=1) as p:
    with open('logfile', 'wb') as logfile:
        for line in p.stdout:
            logfile.write(line)
            sys.stdout.buffer.write(line)
            sys.stdout.buffer.flush()

To call the tee -based command in Python using shell=True : 要使用shell=True在Python中调用基于tee的命令:

#!/usr/bin/env python
from pipes import quote
from subprocess import call

files = input_path, output_path, ddrescue_logfile
rc = call('ddrescue {} |  tee -a drclog'.format(' '.join(map(quote, files))),
          shell=True)

To emulate the script -based command: 要模拟基于script的命令:

#!/usr/bin/env python3
import os
import shlex
import pty

logfile = open('logfile', 'wb')
def read(fd):
    data = os.read(fd, 1024) # doesn't block, it may return less
    logfile.write(data) # it can block but usually not for long
    return data
command = 'ddrescue input_path output_path ddrescue_logfile'
status = pty.spawn(shlex.split(command), read)
logfile.close()

To call screen command in Python: 要在Python中调用screen命令:

#!/usr/bin/env python3
import os
import shlex
from subprocess import check_call

screen_cmd = 'screen -L -- ddrescue input_path output_path ddrescue_logfile'
check_call(shlex.split(screen_cmd))
os.replace('screenlog.0', 'logfile')

对我subprocess.call(["ddrescue $0 $1 | tee -a drclog", in_file_path, out_file_path], shell=True)的解决方案是subprocess.call(["ddrescue $0 $1 | tee -a drclog", in_file_path, out_file_path], shell=True)

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