如何深度复制不规则的2D数组

Question

How can I deep copy an irregularly shaped 2D array in Java?

Ie.

int[][] nums =  {{5},
                 {9,4},
                 {1,7,8},
                 {8,3,2,10}}

I'm unable to use Arrays.arrayCopy() for some reason (versioning?)

Answer 1

int[][] copy = new int[nums.length][];

for (int i = 0; i < nums.length; i++) {
    copy[i] = new int[nums[i].length];

    for (int j = 0; j < nums[i].length; j++) {
        copy[i][j] = nums[i][j];
    }
}

You can replace the second loop with System.arraycopy() or Arrays.copyOf().

Answer 2

I wrote this in Eclipse, tested it, came back and found that João had beaten me to almost exactly the same solution. I upvoted him, but here's mine for comparison. I guess it's instructive to see the very slight details people choose to do differently.

private static int[][] copy2d(int[][] nums) {
    int[][] copy = new int[nums.length][];

    for (int i = 0; i < copy.length; i++) {
        int[] member = new int[nums[i].length];
        System.arraycopy(nums[i], 0, member, 0, nums[i].length);
        copy[i] = member;
    }

    return copy;
}

For extra credit, try writing one that copies an n-dimensional array where n is arbitrary.

Answer 3

N-dimensional deep copy

public class ArrayTest extends TestCase {

    public void testArrays() {
        Object arr = new int[][]{
                {5},
                {9, 4},
                {1, 7, 8},
                {8, 3, 2, 10}
        };

        Object arrCopy = copyNd(arr);
        int height = Array.getLength(arr);
        for (int r = 0; r < height; r++) {
            Object rowOrigonal = Array.get(arr, r);
            Object rowCopy = Array.get(arrCopy, r);
            int width = Array.getLength(rowOrigonal);
            for (int c = 0; c < width; c++) {
                assertTrue(rowOrigonal.getClass().isArray());
                assertTrue(rowCopy.getClass().isArray());
                assertEquals(Array.get(rowOrigonal, c), Array.get(rowCopy, c));
                System.out.println(Array.get(rowOrigonal, c) + ":" + Array.get(rowCopy, c));
            }
        }
    }

    public static Object copyNd(Object arr) {
        if (arr.getClass().isArray()) {
            int innerArrayLength = Array.getLength(arr);
            Class component = arr.getClass().getComponentType();
            Object newInnerArray = Array.newInstance(component, innerArrayLength);
            //copy each elem of the array
            for (int i = 0; i < innerArrayLength; i++) {
                Object elem = copyNd(Array.get(arr, i));
                Array.set(newInnerArray, i, elem);
            }
            return newInnerArray;
        } else {
            return arr;//cant deep copy an opac object??
        }
    }
}

Answer 4

Some folks suggest clone() -- just to be extra clear, clone() on a multi-dimensional array is only a shallow clone. original.clone()[0] == original[0] . But (for primitives) you can use clone() instead of System.arraycopy() once you're down to one-dimensional arrays.

Answer 5

Here is a simple convenient way to copy 2 dimensional arrays (compatible with DEEP copy) :

public static char[][] cloneArray(char[][] array){
 char[][] copy = new char[array.length][];
 for(int i = 0 ; i < array.length ; i++){
  System.arraycopy(array[i], 0, copy[i] = new char[array[i].length], 0, array[i].length);
 }
 return copy;
}

plz note that you simple have to change array type to anything else, like int

Answer 6

Here's one that specializes to deeply cloning int[][] . It also allows any of the int[] to be null .

import java.util.*;

public class ArrayDeepCopy {

    static int[][] clone(int[][] arr) {
        final int L = arr.length;
        int[][] clone = new int[L][];
        for (int i = 0; i < clone.length; i++) {
            clone[i] = (arr[i] == null) ? null : arr[i].clone();
        }
        return clone;
    }

    public static void main(String[] args) {
        int[][] a = {
            { 1, },
            { 2, 3, },
            null,
        };
        int[][] b = a.clone();
        System.out.println(a[0] == b[0]); // "true", meaning shallow as expected!

        b = clone(a); // this is deep clone!
        System.out.println(Arrays.deepEquals(a, b)); // "true"
        System.out.println(a[0] == b[0]); // "false", no longer shallow!
    }
}

Answer 7

Another arbitrary nd copy. It's ugly, and thanks to Java's type system you can't cast the result back to the array type you started with. Still, it works. Like the other comments say, use clone() :)

public  void testMultiDimArray()
{
   int[][][] arr = new int[][][] {
           { {5}, {5, 6 }, {3, 3, 1} },
           { {1, 2, 3}, {4, 5 } }
   };

   Object[] dest = (Object[]) deepCopy(arr);
   // System.out.println(Arrays.deepToString(dest));
   assertTrue(Arrays.deepEquals(arr, dest));
}

public static Object deepCopy(Object src)
{
    int srcLength = Array.getLength(src);
    Class srcComponentType = src.getClass().getComponentType();

    Object dest = Array.newInstance(srcComponentType, srcLength);

    if (srcComponentType.isArray())
    {
        for (int i = 0; i < Array.getLength(src); i++)
            Array.set(dest, i, deepCopy(Array.get(src, i)));
    }
    else
    {
        System.arraycopy(src, 0, dest, 0, srcLength);
    }

    return dest;
}