在Haskell中，最常见的将函数应用于列表的第N个元素的方法是什么？

Question

Its very common where I come across some list of elements xs and want to do something to do something with every Nth element. The simplest example would be the Sieve or Erastothenes, where you want to "knock out" every multiple of a given prime. The two ways I could do this would be explicit recursion passing along a counter variable; or zipWith ($) (cycle (replicate (n-1) id ++ f)) . So which way is better/more elegant/more commonly used, or is there some library function like mapEveryN :: (a -> a) -> Int -> [a] -> [a] that I haven't found?

Answer 1

As you and bheklilr mention, cycle provides a nice way to accomplish this. You can take advantage of laziness a bit though:

mapEvery :: Int -> (a -> a) -> [a] -> [a]
mapEvery n f = zipWith ($) (drop 1 . cycle . take n $ f : repeat id)

The use of zipWith and cycle seems more idiomatic (complex behavior composed from simpler behaviors) than a hand-written recursive function that combines both tasks.

Note : tail here makes this function undefined for n = 0 so drop 1 is preferable.

There isn't a library function for this that I'm aware of.