[英]How to apply if function for every element in a list?
I have a list1 = [3,4,5,6,7,8]
.我有一个
list1 = [3,4,5,6,7,8]
。 I want append to a list2
such that Add 10
to even number
and multiply with 5
if it is an odd number in the list1
with Python.我希望 append 到
list2
中,以便Add 10
到even number
并multiply with 5
,如果它是list1
中的奇数,则使用 Python。
I've tried this我试过这个
list1 = [3, 4, 5, 6, 7, 8]
list2 = []
for num in list1:
if (num%2) == 0:
num + 10
list2.append(num)
else:
num*5
list2.append(num)
list2
got it...知道了...
import numpy as np
list1 = [3, 4, 5, 6, 7, 8]
list2 = []
for num in list1:
if (num%2) == 0:
x = num + 10
list2.append(x)
else:
x = num*5
list2.append(x)
list2
You are not storing num+10
or num*5
anywhere.您没有在任何地方存储
num+10
或num*5
。 Try this -尝试这个 -
list1 = [3, 4, 5, 6, 7, 8]
list2 = []
for num in list1:
if (num%2) == 0:
list2.append(num + 10) #<----
else:
list2.append(num*5) #<----
list2
[15, 14, 25, 16, 35, 18]
You can also try using list comprehension which is a one liner that does the same thing as above -您也可以尝试使用列表理解,它是一种与上述功能相同的内衬 -
list2 = [num+10 if (num%2)==0 else num*5 for num in list1]
[15, 14, 25, 16, 35, 18]
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.