How to apply if function for every element in a list?

Question

I have a list1 = [3,4,5,6,7,8] . I want append to a list2 such that Add 10 to even number and multiply with 5 if it is an odd number in the list1 with Python.

I've tried this

list1 = [3, 4, 5, 6, 7, 8]

list2 = []

for num in list1:
    if (num%2) == 0:
        num + 10
        list2.append(num)
    else:
        num*5
        list2.append(num)

list2

Answer 1

got it...

import numpy as np

list1 = [3, 4, 5, 6, 7, 8]

list2 = []

for num in list1:
    if (num%2) == 0:
        x = num + 10
        list2.append(x)
    else:
        x = num*5
        list2.append(x)

list2

Answer 2

You are not storing num+10 or num*5 anywhere. Try this -

list1 = [3, 4, 5, 6, 7, 8]

list2 = []

for num in list1:
    if (num%2) == 0:
        list2.append(num + 10) #<----
    else:
        list2.append(num*5)    #<----
        
list2

[15, 14, 25, 16, 35, 18]

You can also try using list comprehension which is a one liner that does the same thing as above -

list2 = [num+10 if (num%2)==0 else num*5 for num in list1]

[15, 14, 25, 16, 35, 18]