将对象的所有权从一个unique_ptr转移到C ++ 11中的另一个unique_ptr？

Question

In C++11 we can transfer the ownership of an object to another unique_ptr using std::move() . After the ownership transfer, the smart pointer that ceded the ownership becomes null and get() returns nullptr.

std::unique_ptr<int> p1(new int(42));
std::unique_ptr<int> p2 = std::move(p1); // Transfer ownership

What are the situations where this will be useful as it is transferring the ownership to another unique_ptr ?

Answer 1

The following situations involve transferring ownership from one unique_ptr to another: returning from a function, and passing as a parameter to a function like a constructor.

Say you have some polymorphic type Animal :

struct Animal {
  virtual ~Animal() {}
  virtual void speak() = 0;
};

with concrete subclasses Cat and Dog :

struct Cat : Animal {
  void speak() override { std::cout << "Meow!\n"; }
};

struct Dog : Animal {
  void speak() override { std::cout << "Woof!\n"; }
};

And you want a simple factory that creates a pet based on a required value of obedience. Then the factory must return a pointer. We want the pet factory to transfer ownership of the created pet to the caller so a reasonable return type is std::unique_ptr<Animal> :

std::unique_ptr<Animal> createPet(double obedience) {
  if (obedience > 5.0)
    return std::make_unique<Dog>();
  return std::make_unique<Cat>();
} 

Now, say we want to create a House that will own the pet then we might want to pass the pet into the constructor of the House . There is some debate ( see comments on this blog post ) about how best to pass a unique_ptr to a constructor but it would look something like this:

class House {
 private:
  std::unique_ptr<Animal> pet_;
 public:
  House(std::unique_ptr<Animal> pet) : pet_(std::move(pet)) {}
};

We have passed the unique_ptr into the constructor and have then "moved" it to the member variable.

The calling code could look something like:

  auto pet = createPet(6.0);
  House house(std::move(pet));

After constructing the House , the pet variable will be nullptr because we have transferred ownership of the pet to the House .

Live demo

Answer 2

for example if you call a function you can move your unique_ptr in the parameter list so it can be a part of your function signature

foo ( std::unique_ptr<T>&& ptr )

you can call foo with

foo( std::move(myPtr) );

Note that std::move is an unconditional cast and unique_ptr is an object with a state, and a part of that state is the pointer that that unique_ptr is managing, with std::move you are casting the entire object, you are not really changing anything about ownership, there is nothing peculiar about std::unique_ptr while using std::move because std::move doesn't really care about anything specific, as I said it is an unconditional cast and unique_ptr simply gets casted, the entire object that is an instance of type unique_ptr<T> is casted .

If you want to talk about a transfer of ownership of the object pointed by your unique_ptr , you should consider the swap provided by std::unique_ptr<T> itself .