[英]data not storing into database using php in android
Hi In My Application I am designing a form with name,email,mobile,messages.clicking the submit button I want to save all the records to database.Data not storing into database.and logcat showing this errors. 嗨,在我的应用程序中,我正在设计一个名称,电子邮件,手机,消息的表单。单击提交按钮,我想将所有记录保存到数据库中。数据未存储到数据库中。 Can any one please help me. 谁能帮帮我吗。
AdmissionEnquiry AdmissionEnquiry
public class AdmissionEnquiry extends Activity
{
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.admissionform);
final EditText name=(EditText) findViewById(R.id.name);
final EditText email=(EditText) findViewById(R.id.email);
final EditText mobile=(EditText) findViewById(R.id.mobile);
final EditText address=(EditText) findViewById(R.id.address);
final EditText enqdetails=(EditText) findViewById(R.id.enqdetail);
Button submit = (Button) findViewById(R.id.submit);
submit.setOnClickListener(new OnClickListener() {
public void onClick(View v)
{
if(name.getText().toString().length()==0)
{
name.setError( "Please Enter Name" );
}
else if(email.getText().toString().length()==0)
{
email.setError( "Please Enter Email" );
}
else if(mobile.getText().toString().length()==0)
{
mobile.setError( "Please Enter Mobile" );
}
else if(address.getText().toString().length()==0)
{
address.setError( "Please Enter Address" );
}
else if(enqdetails.getText().toString().length()==0)
{
enqdetails.setError( "Please Enter EnquiryDetails" );
}
else
{
try{
String queryString ="name="+ name
+"&email="+email+"&mobile="+mobile+ "&address"+address+"&enqdetails"+enqdetails;
String data = DatabaseUtility.executeQueryPhp("Admissionform",queryString);
System.out.println(data);
Toast.makeText(
AdmissionEnquiry.this,
"Message:Records Saved Sucessfully",
Toast.LENGTH_SHORT).show();
}
catch (Exception e) {
e.printStackTrace();
}
}
}
});
}
}
Logcat logcat的
10-12 08:03:26.823: E/Fail 1(2341): java.lang.IllegalArgumentException: Illegal character in fragment at index 128: http://10.0.2.2/android_connect/Admissionform.php?name=android.widget.EditText{b2e7b698 VFED..CL ......I. 79,20-320,55 #7f070007 app:id/name}&email=android.widget.EditText{b2e7bf78 VFED..CL ......I. 140,20-320,55 #7f070009 app:id/email}&mobile=android.widget.EditText{b2e746b0 VFED..CL ......I. 149,20-320,55 #7f07000b app:id/mobile}&addressandroid.widget.EditText{b2e13f38 VFED..CL ......I. 77,20-320,55 #7f07000d app:id/address}&enqdetailsandroid.widget.EditText{b2e780e0 VFED..CL .F....I. 135,20-320,55 #7f07000f app:id/enqdetail}
10-12 08:03:26.823: E/Fail 2(2341): java.lang.NullPointerException: lock == null
php PHP
<?php require_once('db/connection.php');
$name = !empty($_POST['name']) ? $_POST['name'] : $_GET['name'];
$email = !empty($_POST['email']) ? $_POST['email'] : $_GET['email'];
$mobile = !empty($_POST['mobile']) ? $_POST['mobile'] : $_GET['mobile'];
$address = !empty($_POST['address']) ? $_POST['address'] : $_GET['address'];
$enqdetails = !empty($_POST['enqdetails']) ? $_POST['enqdetails'] : $_GET['enqdetails'];
$query = "insert into admissionform(name,email,mobile,address,enqdetails) VALUES('$name','$email','$mobile','$address','$enqdetails')";
$json_output = array();
if (!mysql_query($query )) {
$json_output[] = mysql_errno() . ": ".mysql_error();
}else{
$json_output[] = true;
}
print(json_encode($json_output));
mysql_close();
?>
You forgot the = in the queryString 您忘记了queryString中的=
String queryString ="name="+ name
+"&email="+email+"&mobile="+mobile+ "&address"+address+"&enqdetails"+enqdetails;
should be 应该
String queryString ="name="+ name
+"&email="+email+"&mobile="+mobile+ "&address="+address+"&enqdetails="+enqdetails;
EDIT : you should get the strings first like this 编辑:您应该首先获得这样的字符串
public void onClick(View v)
{
final EditText name=(EditText) findViewById(R.id.name);
final EditText email=(EditText) findViewById(R.id.email);
final EditText mobile=(EditText) findViewById(R.id.mobile);
final EditText address=(EditText) findViewById(R.id.address);
final EditText enqdetails=(EditText) findViewById(R.id.enqdetail);
String zname = name.getText().toString();
String zemail = email.getText().toString();
String zmobile = mobile.getText().toString();
String zaddress = address.getText().toString();
String zenqdetails = enqdetails.getText().toString();
...
String queryString ="name="+ zname+"&email="+zemail
+"&mobile="+zmobile+ "&address"+zaddress+"&enqdetails"+zenqdetails;
String data = DatabaseUtility.executeQueryPhp("Admissionform",queryString);
...
}
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