汇编语言程序（求和一个数组中数字的差）
[英]Assembly language program (sum the differences of a number in an array)
问题描述
I have been tasked, with a homework assignment (I'm not going to sugar-coat it), writing a 32-bit assembly program that uses a loop and indexed addressing to calculate the sum of the gaps between successive array elements, which are in non-decreasing order. 
我的任务是进行家庭作业（我不会在上面涂糖），编写一个32位汇编程序，该程序使用循环和索引寻址来计算连续数组元素之间的间隙之和。以非降序排列。 (Ex: dwarray dword 0,2,5,9,10) （例如：dwarray dword 0、2、5、9、10）
What I don't know how to do is subtract the nth element of an array from the nth-1 element in the array using a loop. 我不知道该怎么做是使用循环从数组的第n-1个元素中减去数组的第n个元素。 If I did, then I would store the result in a different register and keep adding the results into that register until the last element has been reached. 如果这样做了，那么我会将结果存储在另一个寄存器中，并继续将结果添加到该寄存器中，直到到达最后一个元素为止。 I'm only looking to be pointed in the right direction (I'm not looking for the answer). 我只是想指出正确的方向（我不在寻找答案）。 Does anyone have any suggestions? 有没有人有什么建议？
1 个解决方案
解决方案1
1 已采纳 2014-10-12 19:41:36
Since you will be using a loop you'll need a loop counter equal to the number of elements in the array minus 1. 由于将使用循环，因此需要一个循环计数器，该计数器等于数组中元素的数量减去1。
Convenient instructions would be add eax,[ebx+ecx*4] and sub eax,[ebx+ecx*4-4] 方便的说明是add eax,[ebx+ecx*4]和sub eax,[ebx+ecx*4-4]
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