多值DWORD枚举作为一个函数参数C ++

Question

I am unable to get this to work. I want to include two values in the first func arg spot(Color and Black).

It works fine with one arg in arg1: func(arg_a::Color, 5);

I tried the following variations in arg1 unsuccessfully:

arg_a::Color || Black arg_a::Color && Black (arg_a::Color, arg_a::Black) DWORD test = arg_a::Color&&Black;

The documentation I have is below: arg_a Type: DWORD

The arg_a can be one or more of the following values: Color White Black

Answer 1

To encode two "enum values" in one, you'd normally use one bit for each value:

enum {
    Black = 0x01;
    White = 0x02;
    Color = 0x04;
}

Then you can combine them with bitwise operators:

call(Black|White);
// or perhaps easier to read
call(Black + White);

On the receiving end

call(int val) {
    if (val & Black) { ... }
    if (val & White) { ... }

Note this is pseudo code only.

Answer 2

try DWORD(arg_a::Black, arg_a::Color) // predefined macro or (arg_a::Black|arg_a::Color) // bitwise or

you are using logical operators but you need some bitwise operations to get this done.