Preg_match（yyyy-mm-dd hh：mm：ss） - 只有这种格式

Question

function Check_Date_Time($date_time)
{
 if (preg_match("/(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})/", $date_time))
   {
     return true;
   }
     else 
     {
     return false;
     }
}   

if(Check_Date_Time($date)){
    //echo 'correct';
}else{
    die();
}

If I set the date as such

["DueDate3"]=> string(24) "2014-10-17 21:10:1751111" 

the validator let its trough, I got no ideas why :/ If it is a properly used date format it returns true. I don't really can use other formats - only this is acceptable

Answer 1

添加start ^并结束$ anchors到你的正则表达式。

if (preg_match("/^(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})$/", $date_time))

Answer 2

 ^  Start of string or line  
\A  Start of string  
 $  End of string or line  
\Z  End of string  

Try to put some of these anchor characters in the code:

preg_match("/^(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})$/", $date_time)

You can find more basic characters for regexp here .

Answer 3

添加锚到你的正则表达式：

 if (preg_match("/^(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})$/", $date_time))

Answer 4

try this regex expression

$date_time = "2019-02-21 11:25:34";
if (preg_match("/^[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (0[0-9]|1[0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$/", $date_time)

this might help you out. Thanks