PHP-在dd / mm / yyyy之间进行SQL搜索，同时具有yyyy-mm-dd hh：mm：ss

Question

I want to show data that from between date that I choose.

Already tried SELECT * from myTable WHERE myDATE BETWEEN LIKE 'datefrom%' AND LIKE 'dateend%' and for CONVERT I still don't get it because haven't found one that have a full query about that.

As my title, my sql field is datetime type and with format 'yyyy-mm-dd hh:mm:ss' while in php I have format dd/mm/yyyy

Please answer this only in PHP code and SQL query and in full mode.

Thank you :)

Answer 1

You can do between YYYY-MM-DD and YYYY-MM-DD (excluding time) in MySQL but MySQL won't understand dd/mm/yyyy so you need to convert it to the proper format.

When you exclude the time, it interprets it at 00:00:00 so depending on your situation, you may want to do between YYYY-MM-DD and YYYY-MM-DD 23:59:59

Note: PHP won't properly interpret dd/mm/yyyy either. PHP date functions understand mm/dd/yyyy and dd-mm-yyyy .

Answer 2

As commenters have said, you will first have to convert your dd/mm/yyyy formatted date to something that MySQL prefers, which is YYYY-mm-dd H:i:s

So, how do you convert your date to MySQL friendly date? Do something like this:

<?php
$datefrom = '25/06/2015';
$dateend = '20/10/2015';

// create an array with dd, mm and yyyy
$splitFrom = explode('/', $datefrom);
$splitTo = explode('/', $dateend);

// mktime takes hour, minutes, seconds, month, day, year arguments
// create timestamp using mktime and pass it to date and format it to
// mysql friendly timestamp
$mysqlFrom = date('Y-m-d H:i:s',  mktime(0, 0, 0, $splitFrom[1], $splitFrom[0], $splitFrom[2]));
$mysqlTo = date('Y-m-d H:i:s',  mktime(0, 0, 0, $splitTo[1], $splitTo[0], $splitFrom[2]));

// echo sprintf("From %s and To %s", $mysqlFrom, $mysqlTo);

// this is where you would do your SQL statement and substitute $mysqlFrom and $mysqlTo dates

?>

Note that this is just a rudimentary example to show you how you can proceed with solving the problem yourself. As time passes, you will have to optimize this kind of code further.