如何编写这个嵌套的Linq To Xml查询
[英]How to write this nested Linq To Xml query
问题描述
Hi I am writing an app for a medical study they will type in the gender, the age, and some other values which will be calculated to a ResultValue 
嗨，我正在为医学研究编写一个应用程序，他们将输入性别，年龄和一些其他值，这些值将计算到ResultValue
now I have an XML file which holds some information about the result in combination of Age, Gender and the ResultValues and I would like to print out the description of the TestResult (in case in which group the proband belong) One thing to note is that I have to deal with value ranges this means the actual value lies between the low part and the high part... I have three groups... OK hier is my XML file 现在我有一个XML文件，其中包含Age，Gender和ResultValues组合结果的一些信息，我想打印出TestResult的描述（如果先证者属于哪个组）需要注意的一件事是我必须处理值范围这意味着实际值位于低部分和高部分之间...我有三个组...好的hier是我的XML文件
<?xml version="1.0" encoding="iso-8859-1"?>
<Result>
<ID>1</ID>
<Description>You belong to Group 1</Description>
<Genders>
<Gender type="female">
<Ages>
<Age low="18" high="24">
<ResultValue low="0" high="19"/>
</Age>
<Age low="25" high="34">
<ResultValue low="0" high="20"/>
</Age>
<Age low="35" high="44">
<ResultValue low="0" high="21"/>
</Age>
<Age low="45" high="54">
<ResultValue low="0" high="22"/>
</Age>
<Age low="55" high="64">
<ResultValue low="0" high="23"/>
</Age>
<Age low="65" high="110">
<ResultValue low="0" high="24"/>
</Age>
</Ages>
</Gender>
<Gender type="male">
<Ages>
<Age low="18" high="24">
<ResultValue low="0" high="19"/>
</Age>
<Age low="25" high="34">
<ResultValue low="0" high="20"/>
</Age>
<Age low="35" high="44">
<ResultValue low="0" high="21"/>
</Age>
<Age low="45" high="54">
<ResultValue low="0" high="22"/>
</Age>
<Age low="55" high="64">
<ResultValue low="0" high="23"/>
</Age>
<Age low="65" high="110">
<ResultValue low="0" high="24"/>
</Age>
</Ages>
</Gender>
</Genders>
</Result>
<Result>
<ID>2</ID>
<Description>You belong to Group 2</Description>
<Genders>
<Gender type="female">
<Ages>
<Age low="18" high="24">
<ResultValue low="19" high="24"/>
</Age>
<Age low="25" high="34">
<ResultValue low="20" high="25"/>
</Age>
<Age low="35" high="44">
<ResultValue low="21" high="26"/>
</Age>
<Age low="45" high="54">
<ResultValue low="22" high="27"/>
</Age>
<Age low="55" high="64">
<ResultValue low="23" high="28"/>
</Age>
<Age low="65" high="110">
<ResultValue low="24" high="29"/>
</Age>
</Ages>
</Gender>
<Gender type="male">
<Ages>
<Age low="18" high="24">
<ResultValue low="19" high="24"/>
</Age>
<Age low="25" high="34">
<ResultValue low="20" high="25"/>
</Age>
<Age low="35" high="44">
<ResultValue low="21" high="26"/>
</Age>
<Age low="45" high="54">
<ResultValue low="22" high="27"/>
</Age>
<Age low="55" high="64">
<ResultValue low="23" high="28"/>
</Age>
<Age low="65" high="110">
<ResultValue low="24" high="29"/>
</Age>
</Ages>
</Gender>
</Genders>
</Result>
<Result>
<ID>3</ID>
<Description>You belong to group 3</Description>
<Genders>
<Gender type="female">
<Ages>
<Age low="18" high="24">
<ResultValue low="24" high="29"/>
</Age>
<Age low="25" high="34">
<ResultValue low="25" high="30"/>
</Age>
<Age low="35" high="44">
<ResultValue low="26" high="31"/>
</Age>
<Age low="45" high="54">
<ResultValue low="27" high="32"/>
</Age>
<Age low="55" high="64">
<ResultValue low="28" high="33"/>
</Age>
<Age low="65" high="110">
<ResultValue low="29" high="34"/>
</Age>
</Ages>
</Gender>
<Gender type="male">
<Ages>
<Age low="18" high="24">
<ResultValue low="24" high="29"/>
</Age>
<Age low="25" high="34">
<ResultValue low="25" high="30"/>
</Age>
<Age low="35" high="44">
<ResultValue low="26" high="31"/>
</Age>
<Age low="45" high="54">
<ResultValue low="27" high="32"/>
</Age>
<Age low="55" high="64">
<ResultValue low="28" high="33"/>
</Age>
<Age low="65" high="110">
<ResultValue low="29" high="34"/>
</Age>
</Ages>
</Gender>
</Genders>
</Result>
What would look my linq to xml query like if I have 什么看起来我的linq到xml查询，如果我有
gender="female" 性别=“女”
age=29 年龄= 29
ResultValue=17 ResultValue = 17
this proband would certainly belong to Group 1 and I would like to print out the matching Description... 这个先证者肯定属于第1组，我想打印出匹配的描述......
But I am banging my head to get this working... 但我正在敲打我的头来让这个工作......
I am looking for a solution in c#... Any help would be great!!! 我正在寻找c＃的解决方案...任何帮助都会很棒!!!
1 个解决方案
解决方案1
6 已采纳 2009-01-08 17:52:51
Something like this? 像这样的东西？
XElement myElement = XElement.Parse(xmlstring);
int resultValue = 17;
int age = 26;
string genderValue = "female";
IEnumerable<string> query =
myElement.Descendants("ResultValue")
.Where(rv => ((int)rv.Attribute("low")) <= resultValue)
.Where(rv => ((int)rv.Attribute("high")) >= resultValue)
.Where(rv => rv.Ancestors("Age")
.Any(a => ((int) a.Attribute("low")) <= age && ((int) a.Attribute("high")) >= age)
)
.Where(rv => ((string)rv.Ancestors("Gender").Single().Attribute("type")) == genderValue)
.Select(rv => rv.Ancestors("Result").Single().Element("Description").Value);
foreach (string x in query)
Console.WriteLine(x);
The idea is that you can imagine a row-column shape where each row is a ResultValue. 这个想法是你可以想象一个行列形状，其中每一行都是ResultValue。 Each result value has a single parent of Age, a single parent of Gender, an a single parent of Result. 每个结果值都有一个Age的父级，Gender的单个父级，Result的单个父级。
ResultValue.Low ResultValue.High Age.Low Age.High Gender.Type Result.Description ResultValue.Low ResultValue.High Age.Low Age.High Gender.Type Result.Description
In fact, one can project the above xml into that shape: 实际上，可以将上面的xml投影到该形状中：
var query2 = myElement.Descendants("ResultValue")
.Select(rv => new
{
ResultValue = rv,
Age = rv.Ancestors("Age"),
Gender = rv.Ancestors("Gender"),
Result = rv.Ancestors("Result")
})
.Select(x => new XElement("Data",
new XAttribute("ResultValue.Low", (int)x.ResultValue.Attribute("low")),
new XAttribute("ResultValue.High", (int)x.ResultValue.Attribute("high")),
new XAttribute("Age.Low", (int)x.Age.Attributes("low").Single()),
new XAttribute("Age.High", (int)x.Age.Attributes("high").Single()),
new XAttribute("Gender.Type", (string) x.Gender.Attributes("type").Single()),
new XAttribute("Result.Description", (string) x.Result.Elements("Description").Single())
));
foreach (XElement x in query2)
Console.WriteLine(x);
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