[英]How to write this nested Linq To Xml query
嗨,我正在為醫學研究編寫一個應用程序,他們將輸入性別,年齡和一些其他值,這些值將計算到ResultValue
現在我有一個XML文件,其中包含Age,Gender和ResultValues組合結果的一些信息,我想打印出TestResult的描述(如果先證者屬於哪個組)需要注意的一件事是我必須處理值范圍這意味着實際值位於低部分和高部分之間...我有三個組...好的hier是我的XML文件
<?xml version="1.0" encoding="iso-8859-1"?>
<Result>
<ID>1</ID>
<Description>You belong to Group 1</Description>
<Genders>
<Gender type="female">
<Ages>
<Age low="18" high="24">
<ResultValue low="0" high="19"/>
</Age>
<Age low="25" high="34">
<ResultValue low="0" high="20"/>
</Age>
<Age low="35" high="44">
<ResultValue low="0" high="21"/>
</Age>
<Age low="45" high="54">
<ResultValue low="0" high="22"/>
</Age>
<Age low="55" high="64">
<ResultValue low="0" high="23"/>
</Age>
<Age low="65" high="110">
<ResultValue low="0" high="24"/>
</Age>
</Ages>
</Gender>
<Gender type="male">
<Ages>
<Age low="18" high="24">
<ResultValue low="0" high="19"/>
</Age>
<Age low="25" high="34">
<ResultValue low="0" high="20"/>
</Age>
<Age low="35" high="44">
<ResultValue low="0" high="21"/>
</Age>
<Age low="45" high="54">
<ResultValue low="0" high="22"/>
</Age>
<Age low="55" high="64">
<ResultValue low="0" high="23"/>
</Age>
<Age low="65" high="110">
<ResultValue low="0" high="24"/>
</Age>
</Ages>
</Gender>
</Genders>
</Result>
<Result>
<ID>2</ID>
<Description>You belong to Group 2</Description>
<Genders>
<Gender type="female">
<Ages>
<Age low="18" high="24">
<ResultValue low="19" high="24"/>
</Age>
<Age low="25" high="34">
<ResultValue low="20" high="25"/>
</Age>
<Age low="35" high="44">
<ResultValue low="21" high="26"/>
</Age>
<Age low="45" high="54">
<ResultValue low="22" high="27"/>
</Age>
<Age low="55" high="64">
<ResultValue low="23" high="28"/>
</Age>
<Age low="65" high="110">
<ResultValue low="24" high="29"/>
</Age>
</Ages>
</Gender>
<Gender type="male">
<Ages>
<Age low="18" high="24">
<ResultValue low="19" high="24"/>
</Age>
<Age low="25" high="34">
<ResultValue low="20" high="25"/>
</Age>
<Age low="35" high="44">
<ResultValue low="21" high="26"/>
</Age>
<Age low="45" high="54">
<ResultValue low="22" high="27"/>
</Age>
<Age low="55" high="64">
<ResultValue low="23" high="28"/>
</Age>
<Age low="65" high="110">
<ResultValue low="24" high="29"/>
</Age>
</Ages>
</Gender>
</Genders>
</Result>
<Result>
<ID>3</ID>
<Description>You belong to group 3</Description>
<Genders>
<Gender type="female">
<Ages>
<Age low="18" high="24">
<ResultValue low="24" high="29"/>
</Age>
<Age low="25" high="34">
<ResultValue low="25" high="30"/>
</Age>
<Age low="35" high="44">
<ResultValue low="26" high="31"/>
</Age>
<Age low="45" high="54">
<ResultValue low="27" high="32"/>
</Age>
<Age low="55" high="64">
<ResultValue low="28" high="33"/>
</Age>
<Age low="65" high="110">
<ResultValue low="29" high="34"/>
</Age>
</Ages>
</Gender>
<Gender type="male">
<Ages>
<Age low="18" high="24">
<ResultValue low="24" high="29"/>
</Age>
<Age low="25" high="34">
<ResultValue low="25" high="30"/>
</Age>
<Age low="35" high="44">
<ResultValue low="26" high="31"/>
</Age>
<Age low="45" high="54">
<ResultValue low="27" high="32"/>
</Age>
<Age low="55" high="64">
<ResultValue low="28" high="33"/>
</Age>
<Age low="65" high="110">
<ResultValue low="29" high="34"/>
</Age>
</Ages>
</Gender>
</Genders>
</Result>
什么看起來我的linq到xml查詢,如果我有
性別=“女”
年齡= 29
ResultValue = 17
這個先證者肯定屬於第1組,我想打印出匹配的描述......
但我正在敲打我的頭來讓這個工作......
我正在尋找c#的解決方案...任何幫助都會很棒!!!
像這樣的東西?
XElement myElement = XElement.Parse(xmlstring);
int resultValue = 17;
int age = 26;
string genderValue = "female";
IEnumerable<string> query =
myElement.Descendants("ResultValue")
.Where(rv => ((int)rv.Attribute("low")) <= resultValue)
.Where(rv => ((int)rv.Attribute("high")) >= resultValue)
.Where(rv => rv.Ancestors("Age")
.Any(a => ((int) a.Attribute("low")) <= age && ((int) a.Attribute("high")) >= age)
)
.Where(rv => ((string)rv.Ancestors("Gender").Single().Attribute("type")) == genderValue)
.Select(rv => rv.Ancestors("Result").Single().Element("Description").Value);
foreach (string x in query)
Console.WriteLine(x);
這個想法是你可以想象一個行列形狀,其中每一行都是ResultValue。 每個結果值都有一個Age的父級,Gender的單個父級,Result的單個父級。
ResultValue.Low ResultValue.High Age.Low Age.High Gender.Type Result.Description
實際上,可以將上面的xml投影到該形狀中:
var query2 = myElement.Descendants("ResultValue")
.Select(rv => new
{
ResultValue = rv,
Age = rv.Ancestors("Age"),
Gender = rv.Ancestors("Gender"),
Result = rv.Ancestors("Result")
})
.Select(x => new XElement("Data",
new XAttribute("ResultValue.Low", (int)x.ResultValue.Attribute("low")),
new XAttribute("ResultValue.High", (int)x.ResultValue.Attribute("high")),
new XAttribute("Age.Low", (int)x.Age.Attributes("low").Single()),
new XAttribute("Age.High", (int)x.Age.Attributes("high").Single()),
new XAttribute("Gender.Type", (string) x.Gender.Attributes("type").Single()),
new XAttribute("Result.Description", (string) x.Result.Elements("Description").Single())
));
foreach (XElement x in query2)
Console.WriteLine(x);
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