Python：如何制作深度为n的嵌套列表？

Question

I want to make a list of list of list... of depth n.

Curently, I use:

a = []
for i in range(n - 1):
    a = [a]
print a

For example, if n = 3 i got [[[ ]]] .

Is it a clearest and more pythonic way to do this?

Answer 1

Yes, I think you've already got the best way. It's faster and doesn't suffer the limits mentioned by @Aleksi

Alternative would be to write a recursive function or use eval

eval('['*n + ']'*n)  # much slower than a for loop!

Answer 2

Is this Pythonic enough?

>>> n = 5
>>> map(lambda i: (lambda f, *a: f(f, [], *a))(lambda rec, k, i: k if i == 2 else rec(rec, [k], i-1), i), [n])
[[[[[]]]]]