检索查询中的最新日期

Question

I was able to fix my previous query, however the results retrieve contains duplicates. I want to retrieve the latest record.

For example:

   id | firstname | lastname | email             |  date
   1  | steven    | smith    | steven@gmail.com     2013-06-10 04:01:25
   2  | Bill      | Johnson  | bill@gmail.com    |  2014-06-10 04:01:25
   3  | steven    | smith    | steven@gmail.com  |  2014-10-10 12:01:25

The return result should be the row with IDs 2 and 3 THe ID 1 should be not returned as the date is older than the ID 3 date

How can I add this to the query below ?

   SELECT
    users.firstname,
    users.lastname,
    DISTINCT(users.email),
    users.pref
   FROM (
    SELECT
        users.firstname,
        users.lastname,
        users.email,
        users.status,
         users.active,

        CONCAT(
            users.preference_1, ',',
            users.preference_2, ',', 
            users.preference_3
        ) AS pref
    FROM users
) AS users

  WHERE  users.status = 1
  AND users.active = 1
  AND users.date = (
SELECT MAX(u.date) FROM users AS u WHERE u.email =  users.email
  )
  LIMIT 10000

Answer 1

1. no need for subselect
2. add: ORDER BY users.date DESC LIMIT 1 this way you sort the list by date and return only the "1st elemet" which is the one with the "biggest/latest" date

Answer 2

Well, looks like you want to fetch the latest row for each user.

Here's a query that can do it. (It also uses subquery. I don't understand the necessity for using subquery to concat though)

SELECT DISTINCT us.email, us.preference FROM users AS us WHERE us.date = (
    SELECT MAX(u.date) FROM users AS u WHERE u.email = us.email
)

This does not fetch all the details you want. But gives you the basic idea about the query you might have to run.