在Python中，使用sorted（）方法是否可以通过优先级字段对字典列表进行排序？

Question

I have a list of dictionaries and I sort them by multiple keys in a given order (1st 'Name', 2nd 'Start' and 3rd 'End'):

sorted_list = sorted(list, key=lambda dict: (dict['Name'], dict['Start'], -dict['End']))

I want the last sorting is done by a priority field:

the dict['Status'] is a string name like "gene", "mRNA", "exon" and "CDS". The name "gene" must be higher than the others and "CDS" lower than the others.

Thanks for your answer,

Answer 1

First advice: don't use builtin-names as variable-names. You will be confused like hell when you try to use them later. Eg

 dict = [1, 2, 3]
 d = dict(a="b")

will fail miserably. So - never call variables list, dict, file, str, int and all the others.

Your actual problem is solved by a simple lookup-table:

priorities = dict(gene=0, CDS=1000)
sorted_list = sorted(list, 
        key=lambda d: (d['Name'], d['Start'], -d['End'], 
        priorities.get(d['Status'], 1)))