有没有一种方法可以重新定义的行为。 python类的运算符？

Question

Here is the problem, I have a class that I would like to define in python to be able to pass the buck onto another class so to speak when a function to the primary class is called. For example:

class Multi_Interface:
    def __init__(self):
        interfaces = [Interface("message A"), Interface("Message B")]
        self.set_interface(0)

    def set_interface(self, interface_index = 0):
        current_interface = self.interfaces[interface_index]
    # @todo: override the .operator to call the member of the current interface.

class Interface:
    def __init__(self, message):
        self.msg = message

    def do_stuff(self, message="I am a parameter"):
        print message + self.msg

mi = Multi_Interface()
mi.do_stuff(message="the internal message is: ")
mi.set_interface(1)
mi.do_stuff(message="the internal message is: ")
mi.do_stuff()

>>> the internal message is: mesage A
>>> the internal message is: mesage B
>>> I am a parameter: mesage B

Is there a way to overload this operator for a class? How would one overload this operator? I have an idea on how to get the method from the child object provided I can get a string in a method.

Answer 1

final solution is as follows

class Multi_Interface:
    def __init__(self):
        self.interfaces = [Interface("message A"), Interface("Message B")]
        self.current_interface = None
        self.set_interface(0)

    def set_interface(self, interface_index = 0):
        self.current_interface = self.interfaces[interface_index]

    def __getattr__(self, name):
        return getattr(self.current_interface, name)

class Interface:
    def __init__(self, message):
        self.msg = message

    def do_stuff(self, message="I am a parameter "):
        print message + self.msg

mi = Multi_Interface()
mi.do_stuff(message="the internal message is: ")
mi.set_interface(1)
mi.do_stuff(message="the internal message is: ")
mi.do_stuff()