[英]memcpy, segmentation fault
i have try to write this code, but i have found a problem with segmentation fault with memcpy ( i have try to see the code with debug) 我已经尝试编写此代码,但是我发现memcpy存在分段错误的问题(我已经尝试通过调试来查看代码)
FILE *tp;
int l = 0;
while ((fgets(buffer, sizeof buffer, tp))) {
// search equal sign
char *equalsign = strchr(buffer, '=');
l++;
// search quote near value
char *q1 = equalsign + 1;
char *q2 = strchr(q1 + 1, '"');
// extract name and value
char* names = strndup(buffer, equalsign - buffer);
char* values = strndup(q1 + 1, q2 - q1 - 1);
memcpy(g_names,names,strlen(names));
memcpy(g_values,values,strlen(values));
free(names);
free(values);
}
with 与
const char* g_names[SIZE] = { 0, };
char* g_values[SIZE] = { 0, };
char buffer[MAXLINE] = {0,};
define as global. 定义为全局。 with the debug i have see that the problem is with memcpy (segmentation fault). 通过调试,我已经看到问题出在memcpy(分段错误)上。 anyone have a suggest? 有人有建议吗? Thanks. 谢谢。 Regards. 问候。
There are at least two problems with your code: First, it is using g_names
as the destination of memcpy
, which copies the characters over the array of pointers. 您的代码至少存在两个问题:首先,它将g_names
用作memcpy
的目标,该目标将字符复制到指针数组上。 You should be copying to g_names[l]
(assuming l
was to be the index in the g_names
array). 您应该复制到g_names[l]
(假设l
是g_names
数组中的索引)。
Second, your code is missing the actual allocation of g_names[l]
, something like: 其次,您的代码缺少g_names[l]
的实际分配,例如:
g_names[l] = malloc(strlen(names) + 1);
But since you're calling strndup
anyway, you can simply store the result of that call into the array: 但是由于无论如何都调用strndup
,因此您可以简单地将该调用的结果存储到数组中:
// search for equal sign
char *equalsign = strchr(buffer, '=');
// search quote near value
char *q1 = equalsign + 1;
char *q2 = strchr(q1 + 1, '"');
// extract name and value
g_names[l] = strndup(buffer, equalsign - buffer);
g_values[l] = strndup(q1 + 1, q2 - q1 - 1);
l++;
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