[英]Segmentation fault in a list with memcpy
I'm trying to copy a list into another list with memcpy, but I'm getting a segmentation fault everytime I try to access the value I copied. 我正在尝试使用memcpy将列表复制到另一个列表中,但每次尝试访问我复制的值时,我都会遇到分段错误。
I've already tried moving pointers around, but the problem still occurs. 我已经尝试过移动指针,但问题仍然存在。 create_list creates a new head node for the list and returns it. create_list为列表创建一个新的头节点并返回它。 Here is some of the code: 以下是一些代码:
/* The n variable shows the number of elements in the list for the head */
struct list {
union{
void *data;
struct {
unsigned num;
List *end;
};
};
List *node;
};
List *
create_list()
{
List *head;
head = malloc(sizeof(List));
if (head == NULL)
return NULL;
head->num = 0;
head->end = NULL;
head->node = NULL;
return head;
}
int
cpy_list(List *l1, List **l2)
{
List *iter;
void *data_aux;
*l2 = create_list();
iter = l1->node;
while (iter != l1->end) {
memcpy(&data_aux, iter->data, sizeof(iter->data));
//printf("data_aux: %s\n", data_aux);
insert_list(*l2, data_aux, NULL);
//printf("iter->data: %s\n", iter->data);
iter = iter->node;
}
return 1;
}
void
print_list(List *head)
{
List *iter;
iter = head->node;
printf("[");
while (iter != head->end) {
printf("\"%s\",", iter->data);
iter = iter->node;
}
printf("\"%s\"", iter->data);
printf("]");
printf("\n");
}
int
main(int argc, char *argv[])
{
List *l1, *l2;
char *str[] = {"Test0", "Test1", "Test2", "Test3", "Test4"};
void *data_aux;
l1 = create_list();
for (int k = 0; k < 5; k++) {
insert_list(l1 ,str[k], NULL);
}
printf("l1: ");
print_list(l1);
cpy_list(l1, &l2);
print_list(l2);
return 0;
}
memcpy(&data_aux, iter->data, sizeof(iter->data));
I'll assume this is a typo problem (let me know if it is not and you intended to use it like that). 我会假设这是一个拼写错误的问题(如果不是,请告诉我,你打算像那样使用它)。 &data_aux
will return the address of variable data_aux
, not the address pointed by data_aux
. &data_aux
将返回变量data_aux
的地址,而不是data_aux
指向的地址。 This code is likely causing a stack overflow as you are probably writing data beyond the boundaries of the local variable data_aux
(which have the size of a pointer - 4 bytes on x86 or 8 bytes on x64). 此代码可能导致堆栈溢出,因为您可能正在写入超出局部变量data_aux
边界的数据(其大小为指针 - x86上为4个字节或x64上为8个字节)。 If iter->data
have a significant size you will corrupt the stack and have undefined behavior. 如果iter->data
具有相当大的大小,则会破坏堆栈并具有未定义的行为。
What you probably want is to allocate a buffer to be pointed by data_aux
. 你可能想要的是分配一个由data_aux
指向的data_aux
。 Something like: 就像是:
data_aux = malloc(sizeof(iter->data));
And then pass data_aux
instead of &data_aux
in your call to memcpy
. 然后在调用memcpy
传递data_aux
而不是&data_aux
。
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